class
solution
for(
int i =
0; i < nums2.length ; i++)}
return arrays.
copyofrange
(ans,
0, index);}
}
class
solution
for(
int i =
0; i < nums2.length;i++
)else}}
return arrays.
copyofrange
(ans,
0, index);}
}
class
solution
for(
int i =
0; i < s.
length()
;i ++
)for
(int i =
0; i < t.
length()
; i++)if
(count >0)
else}}
return
true;}
}
class
solution
int[
] ans =
newint[26
];//26個英文本母
//字串s出現字元加1，字串t出現字元減1
for(
int i =
0;i < s.
length()
; i++
)//若ans中有不為0的數，則說明s與t中的字元出現的次數至少有乙個不相等
for(
int i =
0;i < ans.length;i++)}
return
true;}
}
class
solution
return n ==1;
}public
intadd
(int n)
return sum;
}}
class
solution
hashmap
hm =
newhashmap
<
>()
;for
(int i =
0; i < str.length ; i ++)}
return
true;}
}
class
solution
else
if(map.
get(ch1)
!= ch2)
return
false;}
return
true;}
}
class
solution
}return
true;}
}
class
solution
//用list來儲存map集合
list
> list =
newarraylist
>
(hm.
entryset()
);//list排序，重寫排序器，根據從大到小排序
list.
sort
(new
comparator
>()
});//輸出每個字元出現的次數，並新增到sb中，最終轉換為字串輸出
for(
int i =
0; i < list.
size()
; i++)}
return sb.
tostring()
;}}
class
solution
else
if(sum <0)
else}}
return list;
}}
class
solution
for(
int i =
0; i < nums.length;i++
) left++
; right--
;while
(left < right && nums[left]
== nums[left-1]
) left++
;while
(left < right && nums[right]
== nums[right+1]
) right--;}
else
if(sum < target)
else}}
}return list;
}}
class
solution
for(
int i =
0; i < nums.length -
3;i++
)//剪枝操作
if(nums[i]
+ nums[i +1]
+ nums[i +2]
+ nums[i +3]
> target)
if(nums[i]
+ nums[length -3]
+ nums[length -2]
+ nums[length -1]
< target)
for(
int j = i+
1; j < nums.length-
2; j++)if
(nums[i]
+ nums[j]
+ nums[length -2]
+ nums[length -1]
< target)
int left = j+1;
int right = nums.length -1;
while
(left < right)
else
if(sum < target)
else}}
}return list;
}}
class
solution
if(sum == target)
else
if(sum < target)
else}}
return best;
}}
class
solution
}for
(int i =
0; i < length ;i++)}
}return result;
}}
class
solution
//每次都壓入，將所有str分組
hm.get(s)
.add
(value);}
return
newarraylist
<
>
(hm.
values()
);}}
class
solution
for(map.entry
entry: hm.
entryset()
)}} hm.
clear()
;}return result;
}}
class
solution
hs.add(nums[i]);
if(hs.
size()
> k)
}return
false;}
}
class
solution
ts.add(
(long
)nums[i]);
if(ts.
size()
> k)
}return
false;}
}
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