scala元組及拉鍊操作：
scala裡面的元組是可是不同資料型別的
scala>("scala",1)
res45: (string, int) = (scala,1)
scala>val t = ("scala",100l,3.14,("spark",1))
t:(string, long, double, (string, int))= (scala,100,3.14,(spark,1))
scala>t._1//元組內空的提取，以下標為1開始，並用._後跟數字的方式進行提取內容
res46: string = scala
scala>t._3
res47: double = 3.14
scala>t._4._1
res48: string = spark
scala>val t,(a,b,c,d) = ("scala",100l,3.14,("spark",1))//可以定義元組時給予變數名，如 t,(a, b, c, d),使用時直接用變數名a,b,c,d即可訪問對應內容
t: (string, long, double, (string, int)) = (scala,100,3.14,(spark,1))
a: string = scala
b: long = 100
c: double = 3.14
d: (string, int) = (spark,1)
scala>a
res49: string = scala
scala>val arr = array(("tingting",1),("ningning",3),("huihui",5))
arr: array[(string, int)] = array((tingting,1), (ningning,3), (huihui,5))
scala>val mp =arr.tomap
mp:scala.collection.immutable.map[string,int] = map(tingting -> 1, ningning -> 3, huihui -> 5)
scala拉鍊操作：
scala>val arr1 = array("dog","cat","mouse")
arr1: array[string] = array(dog, cat, mouse)
scala>val arr2 = array(1,3,5)
arr2: array[int] = array(1, 3, 5)
scala>arr1 zip arr2//拉鍊操作符
res50: array[(string, int)] = array((dog,1), (cat,3), (mouse,5))
scala>arr2 zip arr1//拉鍊操作符
res51: array[(int, string)] = array((1,dog), (3,cat), (5,mouse))
scala>arr1.zip(arr2)//拉鍊操作符
res52: array[(string, int)] = array((dog,1), (cat,3), (mouse,5))
scala>val arr3 = array(1,2,3,4,5)//生成乙個比arr1元素多的陣列，用少的去zip多的
arr3: array[int] = array(1, 2, 3, 4, 5)
scala>arr1 zip arr3//會把長的給擷取掉了
res53: array[(string, int)] =array((dog,1), (cat,2), (mouse,3))
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