zip主要用於關聯兩個集合,關聯的結果可以是array,list等等,然後集合中的元素成為二元tuple
//建立乙個array
scala>
var names=array(
"zhangsan"
,"lisi"
,"wangmazi"
)names: array[
string
]= array(zhangsan, lisi, wangmazi)
//建立另乙個array scores
scala>
val scores=array(60,
70,90)
scores: array[
int]
= array(60,
70,90)
//利用zip關聯兩個array,形成乙個新的array,array中的每個元素是乙個tuple,詳見tuple
scala> names.zip(scores)
res0: array[
(string
,int)]
= array(
(zhangsan,60)
,(lisi,70)
,(wangmazi,90)
)//zip關聯的另一種寫法
scala> names zip scores
res1: array[
(string
,int)]
= array(
(zhangsan,60)
,(lisi,70)
,(wangmazi,90)
)//建立乙個seq
scala>
val nums=seq(0,
1,2,
3,4)
nums: seq[
int]
= list(0,
1,2,
3,4)
//建立乙個list
scala>
val series=list(
"a",
"b",
"c")
series: list[
string
]= list(a, b, c)
//關聯2個list和seq,任意集合均可關聯,集合長度不一樣時候以短的為準
scala> nums.zip(series)
res5: seq[
(int
,string)]
= list((0
,a),(1
,b),(2
,c))
//關聯也有主動被動的問題
scala> series.zip(nums)
res6: list[
(string
,int)]
= list(
(a,0),
(b,1),
(c,2))
//關聯集合長度不一樣時可以用預設值處理.
scala> nums.zipall(series,
"a",20)
res7: seq[
(any
,any)]
= list((0
,a),(1
,b),(2
,c),(3
,20),
(4,20
))scala> series.zipall(nums,
"a",20)
res8: list[
(string
,int)]
= list(
(a,0),
(b,1),
(c,2),
(a,3),
(a,4))
scala> series
res9: list[
string
]= list(a, b, c)
//關聯索引和元素自身
scala> series.zipwithindex
res10: list[
(string
,int)]
= list(
(a,0),
(b,1),
(c,2))
//關聯時自定義索引的起始位置
scala>
val ps=series.zip(stream from 10
)ps: list[
(string
,int)]
= list(
(a,10),
(b,11),
(c,12))
//如果想解除關聯,恢復自由身
scala> ps unzip
warning: there was one feature warning; re-run with
-feature for details
res12:
(list[
string
], list[
int])=
(list(a, b, c)
,list(10,
11,12)
)
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