1、利用to_days函式查詢今天的資料： select * from 表名 where to_days(時間欄位名) = to_days(now()); to_days函式：返回從2023年（公元1年）至當前日期的總天數。
2、昨天 select * from 表名 where to_days( now( ) ) – to_days( 時間欄位名) <= 1
3.7天 select * from 表名 where date_sub(curdate(), interval 7 day) <= date(時間欄位名)
4.近30天 select * from 表名 where date_sub(curdate(), interval 30 day) <= date(時間欄位名)
5.本月 select * from 表名 where date_format( 時間欄位名, 『%y%m' ) = date_format( curdate( ) , 『%y%m' )
6.上一月 select * from 表名 where period_diff( date_format( now( ) , 『%y%m' ) , date_format( 時間欄位名, 『%y%m' ) ) =1
#查詢本季度資料 select * from `ht_invoice_information` where quarter(create_date)=quarter(now());
#查詢上季度資料 select * from `ht_invoice_information` where quarter(create_date)=quarter(date_sub(now(),interval 1 quarter));
#查詢本年資料 select * from `ht_invoice_information` where year(create_date)=year(now());
#查詢上年資料 select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));
查詢當前這週的資料 select name,submittime from enterprise where yearweek(date_format(submittime,'%y-%m-%d')) = yearweek(now());
查詢上週的資料 select name,submittime from enterprise where yearweek(date_format(submittime,'%y-%m-%d')) = yearweek(now())-1;
查詢當前月份的資料 select name,submittime from enterprise where date_format(submittime,'%y-%m')=date_format(now(),'%y-%m')
查詢距離當前現在6個月的資料 select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
查詢上個月的資料
select name,submittime from enterprise where date_format(submittime,'%y-%m')=date_format(date_sub(curdate(), interval 1 month),'%y-%m') select * from ` user ` where date_format(pudate, 『 %y%m 『 ) = date_format(curdate(), 『 %y%m 『 ) ; select * from user where weekofyear(from_unixtime(pudate,'%y-%m-%d')) = weekofyear(now()) select * from user where month (from_unixtime(pudate, 『 %y-%m-%d 『 )) = month (now()) select *from [ user ]where year (from_unixtime(pudate, 『 %y-%m-%d 『 )) = year (now())and month (from_unixtime(pudate, 『 %y-%m-%d 『 )) = month (now()) select *from [ user ]where pudate between 上月最後一天and 下月第一天where date(regdate) = curdate(); select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now()) select date( c_instime ) ,curdate( ) from `t_score` where 1 limit 0 , 30`
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