思路：限制每個點的度數為2 ，邊界點的度數可以花費1的代價減少1個度數
坑點：我tm以後再也不用 ++ r 的優先順序了，這個玩意在 c++ 和 c++11中不一樣，而且tm錯都不知道咋錯的，我tm調了乙個晚上就tm這麼沒了。。。。
#include using namespace std;
typedef int lint;
typedef long long ll;
const int inf = 0x3f3f3f3f;
const int maxr = 55;
const int maxc = 55;
struct edge ;
namespace mfmc
void add(int u, int v, int cap,int cost) ;
he[u] = tot++;
}void add(int u, int v, int cap,int cost)
//o(ve)
//record_e[i]是fa[i]->i的邊的編號
templatevoid spfa(int s, dt dist, int rec) }}
}}
templatevoid dijkstra(int s, dt dist, int rec) }}
}//need dijkstra_graph_edges_pq
//o(fe log(e)),f is the maximum flow
templatevoid mfmc(int s, int t, ft &maxflow, ct &mincost) else
if (inf == dist[t])
break;
ft minf = numeric_limits::max();
for (int e = rec_e[t]; ~e; e = rec_e[edge[e].from])
minf = min(minf, (ft) edge[e].cap);
maxflow += minf;
realdist += dist[t];
mincost += minf * realdist;
for (int e = rec_e[t]; ~e; e = rec_e[edge[e].from])
for (int e = 0; e < tot; ++e) }}
};char str[maxr][maxc];
int dir[4][2] = ,,, };
int r,c;
int calc( int x,int y )
int main();
r--;
c= strlen(str[1]+1);
int s = 0,t = r*c+1,ss = t+1,tt = t+2;
mfmc::init(tt);
mfmc::add( t,s,inf,0 );
int res = 0;
for( int i = 1;i <= r;i++ )
}}else }}
int maxflow,mincost;
mfmc::mfmc( ss,tt,maxflow,mincost );
if( maxflow != res )else
return 0;
}
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