關於oracle 拆分字串加列轉行的問題

我有這樣一張表vvv 類似

jpczzh0000000004[,]

jpczzh_id

jpczzhjsyear1

jpczzhchndjsnrjgm1

jpczzhjsyear2

jpczzhchndjsnrjgm2

1jpczzh0000000004

'2013'

'22'

'121'

'22'

裡的內容都拆成字段。冒號前面的是欄位名(欄位名要依次加123的)，後面是值，大括號括的有n組內容，就拆出來n乘以3個字段來。

下面是我的解決辦法

先建乙個檢視

create or replace view v_szh$ndjsnrjgm as

select rn,
jpczzh_id,
p1,substr(cv0, 0, instr(cv0, ':', 1, 1) - 1) || p1 a,
substr(cv0, instr(cv0, ':', 1, 1) + 1) b
from (select t.rn,t.jpczzh_id,t.p1,
substr(t.ca,
instr(t.ca, ',', 1, c.lv) + 1,
instr(t.ca, ',', 1, c.lv + 1) - (instr(t.ca, ',', 1, c.lv) + 1)) as cv0
from (select result1.rn rn,p1,jpczzh_id,',' || cv1 || ',' as ca,
length(cv1 || ',') - nvl(length(regexp_replace(cv1, ',', '')), 0) as cnt
from (select t1.rn,t1.jpczzh_id,c1.lv as p1,
substr(t1.ca,
instr(t1.ca, '},', 1, c1.lv) + 2,
instr(t1.ca, '},', 1, c1.lv + 1) -
(instr(t1.ca, '},', 1, c1.lv) + 2)) as cv1
from (select rownum rn,jpczzh_id,
'},' || regexp_replace(jpczzh_ch_ndjsnrjgm ,'\[\]','') || '},' as ca,
(length(regexp_replace(jpczzh_ch_ndjsnrjgm,'\[\]','') || '},') -
nvl(length(regexp_replace(jpczzh_ch_ndjsnrjgm,'\[,|}\]','')),0)) / 2 as cnt
from jnjp_project_czzh) t1,
(select level lv from dual connect by level <= 10) c1
where c1.lv <= t1.cnt) result1) t,
(select level lv from dual connect by level <= 10) c
where c.lv <= t.cnt
order by jpczzh_id, p1, lv);

出來的結果是這樣的：

rnjpczzh_id               p1 a                            b

11jpczzh00000000041jpczzhjsyear1            '2013'
21jpczzh00000000041jpczzhchndjsnrjgm1    '22'
31jpczzh00000000042jpczzhjsyear2           '121'
41jpczzh00000000042jpczzhchndjsnrjgm2   '22'

然後再查詢：

select *  

from vvv  t
left join (select jpczzh_id id,
max(decode(a, 'jpczzhjsyear1', b)) jpczzhjsyear1,
max(decode(a, 'jpczzhchndjsnrjgm1', b)) jpczzhchndjsnrjgm1,
max(decode(a, 'jpczzhjsyear2', b)) jpczzhjsyear2,
max(decode(a, 'jpczzhchndjsnrjgm2', b)) jpczzhchndjsnrjgm2,
max(decode(a, 'jpczzhjsyear3', b)) jpczzhjsyear3,
max(decode(a, 'jpczzhchndjsnrjgm3', b)) jpczzhchndjsnrjgm3,
max(decode(a, 'jpczzhjsyear4', b)) jpczzhjsyear4,
max(decode(a, 'jpczzhchndjsnrjgm4', b)) jpczzhchndjsnrjgm4,
max(decode(a, 'jpczzhjsyear5', b)) jpczzhjsyear5,
max(decode(a, 'jpczzhchndjsnrjgm5', b)) jpczzhchndjsnrjgm5
from v_szh$ndjsnrjgm
group by jpczzh_id) ndjsnrjgm
on ndjsnrjgm.id = t.jpczzh_id

得出結果：

jpczzh_id

jpczzhjsyear1

jpczzhchndjsnrjgm1

jpczzhjsyear2

jpczzhchndjsnrjgm2

1jpczzh0000000004

'2013'

'22'

'121'

'22'

不知道還有沒有好的解決辦法，如果有的話請大家指教

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