oracle拆分字串並查詢

樣例sql:

select gro.*,

regexp_substr(group_name, '[^/]+', 1, 1) as one_group,
regexp_substr(group_name, '[^/]+', 1, 2) as two_group,
regexp_substr(group_name, '[^/]+', 1, 3) as three_group,
cfg.address as address
left join (select dbms_lob.substr(wm_concat(office.address)) address,
grop.id
where office.id in
(select regexp_substr(grop.work_address_id,
'[^,]+',
1,rownum)
from dual
connect by rownum <=
length(grop.work_address_id) -
length(replace(grop.work_address_id, ',')) + 1)
group by grop.id) cfg on cfg.id = gro.id

最內層的sql作用為根據將組合id拆分成id的乙個集合，可以使用in關鍵字進行處理；

首先以正則進行字串擷取，因為regexp_substr的第4個引數為分隔組的第幾位，由於是不確定的，所以後面通過connect by 來限制分隔組有幾個，通過字串的長度，去掉分隔符，獲取長度大小。

倒數第二層則通過wm_concat函式進行合併，dbms_lob.substr函式將clob轉換成varchar.

最外一層則為關聯

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