table:failed
+--------------+---------+table:| column name | type |
+--------------+---------+
| fail_date | date |
+--------------+---------+
該錶主鍵為 fail_date。
該錶包含失敗任務的天數.
succeeded
+--------------+---------+系統 每天 執行乙個任務。每個任務都獨立於先前的任務。任務的狀態可以是失敗或是成功。| column name | type |
+--------------+---------+
| success_date | date |
+--------------+---------+
該錶主鍵為 success_date。
該錶包含成功任務的天數.
編寫乙個 sql 查詢 2019-01-01 到 2019-12-31 期間任務連續同狀態period_state的起止日期（start_date和end_date）。即如果任務失敗了，就是失敗狀態的起止日期，如果任務成功了，就是成功狀態的起止日期。
最後結果按照起始日期start_date排序
查詢結果樣例如下所示:
failed table:+-------------------+
| fail_date |
+-------------------+
| 2018-12-28 |
| 2018-12-29 |
| 2019-01-04 |
| 2019-01-05 |
+-------------------+
succeeded table:
+-------------------+
| success_date |
+-------------------+
| 2018-12-30 |
| 2018-12-31 |
| 2019-01-01 |
| 2019-01-02 |
| 2019-01-03 |
| 2019-01-06 |
+-------------------+
result table:
+--------------+--------------+--------------+
| period_state | start date | end date |
+--------------+--------------+--------------+
| present | 2019-01-01 | 2019-01-03 |
| missing | 2019-01-04 | 2019-01-05 |
| present | 2019-01-06 | 2019-01-06 |
+--------------+--------------+--------------+
結果忽略了 2018 年的記錄，因為我們只關心從 2019-01-01 到 2019-12-31 的記錄
從 2019-01-01 到 2019-01-03 所有任務成功，系統狀態為 "succeeded"。
從 2019-01-04 到 2019-01-05 所有任務失敗，系統狀態為 "failed"。
從 2019-01-06 到 2019-01-06 所有任務成功，系統狀態為 "succeeded"。
couchpotato613
發布於 1 個月前
109 閱讀
我是這樣想的：
先按照日期遞增的順序把失敗的和成功的天數連續查出來，sql如下：
select date,period_state from (
select fail_date as date,'failed' as period_state from failed
where fail_date between '2019-01-01' and '2019-12-31'
union all
select success_date as date,'succeeded' as period_state from succeeded
where success_date between '2019-01-01' and '2019-12-31'
) t1 order by t1.date as
sql如下：
select date,period_state,
if(@prev = period_state ,@tmp := @tmp, @tmp := @tmp + 1) as rank,
@prev := period_state as prev from
(select date,period_state from (
select fail_date as date,'failed' as period_state from failed
where fail_date between '2019-01-01' and '2019-12-31'
union all
select success_date as date,'succeeded' as period_state from succeeded
where success_date between '2019-01-01' and '2019-12-31'
) t1 order by t1.date asc) t2,(select @prev := null,@tmp := 0) as init
完整的sql如下:
select t3.period_state as period_state,min(date) as start_date,
max(date) as end_date from
(select date,period_state,
if(@prev = period_state ,@tmp := @tmp, @tmp := @tmp + 1) as rank,
@prev := period_state as prev
from
(select date,period_state from (
select fail_date as date,'failed' as period_state from failed
where fail_date between '2019-01-01' and '2019-12-31'
union all
select success_date as date,'succeeded' as period_state from succeeded
where success_date between '2019-01-01' and '2019-12-31'
) t1 order by t1.date asc) t2,(select @prev := null,@tmp := 0) as init) t3
group by rank
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