MYSQL 時間查詢

select curdate() as 當前日期;

select now() as 當前時間;

select date_format(curdate(),'%w') as 當前週幾;

select date_format( subdate(curdate(),date_format(curdate(),'%w')-1), '%y-%m-%d 00:00:00') as 本周一;

select date_sub(curdate(),interval weekday(curdate()) + 1 day) 本週第一天(周天);

select date_format( subdate(curdate(),date_format(curdate(),'%w')-7), '%y-%m-%d 23:59:59') as 本週末;

select date_sub(curdate(),interval weekday(curdate()) - 5 day) 本週最後一天（週六）;

select date_sub(curdate(),interval weekday(curdate()) + 8 day) 上週第一天(周天);

select date_sub(curdate(),interval weekday(curdate()) + 2 day) 上週最後一天（週六）;

select date_format(curdate(),'%y-%m-01 00:00:00') as 本月第一天;

select date_add(curdate(), interval - day(curdate()) + 1 day) 本月第一天;

select last_day(curdate()) 本月最後一天;

select date_add(curdate()-day(curdate())+1,interval -1 month) 上月第一天;

select last_day(date_sub(now(),interval 1 month)) 上月最後一天;

select date_add(curdate()-day(curdate())+1,interval 1 month) 下月第一天;

select last_day(date_sub(now(),interval -1 month)) 下月最後一天;

select day(last_day(curdate())) 本月天數;

select date_sub(curdate(), interval 1 month) 上月今天的當前日期;

select unix_timestamp(date_sub(now(),interval 1 month)) 上月今天的當前時間（時間戳）;

select datediff(curdate(), date_sub(curdate(), interval 1 month)) 獲取當前時間與上個月之間的天數;

select * from report where create_time between date_format(curdate(),'%y-%m-01 00:00:00') and now(); -- 本月資料

select * from report where date_format(create_time, '%y%m') = date_format(curdate(), '%y%m'); -- 本月資料

select quarter(curdate()) as 當前季度;

select concat(date_format(last_day(makedate(extract(year from curdate()),1) + interval quarter(curdate())*3-3 month),'%y-%m-'),'01') as 本季度第一天;

select last_day(makedate(extract(year from curdate()),1) + interval quarter(curdate())*3-1 month) as 本季度最後一天;

select * from report where quarter(create_time)=quarter(now()); -- 本季度資料

select date_sub(curdate(), interval dayofyear(curdate())-1 day) 本年第一天;

select curdate() - interval(dayofyear(curdate()) - 1) day 本年第一天;

select concat(year(curdate()),'-12-31') 本年最後一天;

select date_sub(curdate(), interval dayofyear(curdate()) day) 上年最後一天;

select (curdate() - interval(dayofyear(curdate()) - 1) day) + interval 1 year 下年第一天;