我理解你的問題是每乙個使用者id在乙個部門中所有的許可權，你給的資料好像不詳細，我新增了一些資料，你看看滿足需求不。sql> with authority as (
2 select '3029' kuid,'205' krid,'21' kdid from dual union all
3 select '3029' kuid,'206' krid,'21' kdid from dual union all
4 select '3029' kuid,'209' krid,'21' kdid from dual union all
5 select '3030' kuid,'205' krid,'10080' kdid from dual union all
6 select '3030' kuid,'206' krid,'10080' kdid from dual union all
7 select '3030' kuid,'209' krid,'10080' kdid from dual union all
8 select '3029' kuid,'205' krid,'10080' kdid from dual union all
9 select '3029' kuid,'206' krid,'10080' kdid from dual union all
10 select '3029' kuid,'209' krid,'10080' kdid from dual
11 ),
12 dept as (
13 select '0' kdid,'-1' kdpid from dual union all
14 select '10080' kdid,'0' kdpid from dual union all
15 select '21' kdid,'10080' kdpid from dual union all
16 select '1' kdid,'-1' kdpid from dual union all
17 select '20080' kdid,'1' kdpid from dual union all
18 select '31' kdid,'20080' kdpid from dual
19 )
20 select distinct t1.kuid,
21 t1.krid,
22 t2.kdid kdpid
23 from authority t1
24 inner join (select t.*,
25 connect_by_root(t.kdid) root_id
26 from dept t
27 start with t.kdid is not null
28 connect by prior t.kdpid = t.kdid) t2 on t1.kdid = t2.root_id
29 order by kuid,
30 kdpid,
31 krid
32 ;
kuid krid kdpid
3029 205 0
3029 206 0
3029 209 0
3029 205 10080
3029 206 10080
3029 209 10080
3029 205 21
3029 206 21
3029 209 21
3030 205 0
3030 206 0
3030 209 0
3030 205 10080
3030 206 10080
3030 209 10080
15 rows selected
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