(1)用隨機函式生成10個3位整數(100~999),把這些整數存於鍊錶中;
(2)輸出鍊錶的內容;
(3)讀入乙個整數,檢視該整數是否在表中,若在,輸出其位置(首位置為1);
(4)讀入乙個整數,以及要插入的位置,把該整數插入到鍊錶中,輸出鍊錶的內容(要求判斷輸入的位置是否合理);
(5)讀入乙個整數,若該整數在煉表裡,刪除該整數,輸出鍊錶的內容;
(6)把鍊錶的內容翻轉,輸出鍊錶的內容。
生成函式生成100~999
#include
cout <<
"隨機生成三位整數,並存入鍊錶中"
<< endl;
srand((
int)
time(0
));p-
>date =
rand()
%899
+100
;
#include
#include
#define ok 1
#define error 0
using
namespace std;
typedef
int status;
typedef
int elemtype;
typedef
struct lnode lnode,
*linklist;
status initlist
(linklist &l)
status putlist
(linklist &l)
cout << endl;
return ok;
}status showlist
(linklist &l)
cout << endl;
return ok;
}int
locateelem
(linklist l, elemtype e)
return j;
}status listinsert
(linklist &l,
int i, elemtype &e)if(
!p || j > i -1)
return error;
s->date = e;
s->next = p-
>next;
p->next = s;
return ok;
}status listdelete
(linklist &l,
int a)
q = p-
>next;
p->next = q-
>next;
delete q;
return ok;
}status returnlist
(linklist &l, linklist &l1)
return ok;
}int
main()
else
cout <<
"插入失敗"
<< endl;
break
;case3:
cout <<
"請輸入要刪除的數字:"
; cin >> a;if(
listdelete
(l, a)
)else
cout <<
"刪除失敗"
<< endl;
break
;case4:
if(returnlist
(l, l1)
)else
cout <<
"資料翻轉失敗!"
<< endl;
break
;case5:
cout <<
showlist
(l)<< endl;}}
}
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