LeetCode陣列 有效的數獨

2021-08-28 18:56:23 字數 2081 閱讀 4855

有效的數獨

判斷乙個 9x9 的數獨是否有效。只需要根據以下規則,驗證已經填入的數字是否有效即可。

數字 1-9 在每一行只能出現一次。

數字 1-9 在每一列只能出現一次。

數字 1-9 在每乙個以粗實線分隔的 3x3 宮內只能出現一次。

上圖是乙個部分填充的有效的數獨。

數獨部分空格內已填入了數字,空白格用 『.』 表示。

示例 1:

輸入:

[ ["5","3",".",".","7",".",".",".","."],

["6",".",".","1","9","5",".",".","."],

[".","9","8",".",".",".",".","6","."],

["8",".",".",".","6",".",".",".","3"],

["4",".",".","8",".","3",".",".","1"],

["7",".",".",".","2",".",".",".","6"],

[".","6",".",".",".",".","2","8","."],

[".",".",".","4","1","9",".",".","5"],

[".",".",".",".","8",".",".","7","9"]

]輸出: true

示例 2:

輸入:

[ ["8","3",".",".","7",".",".",".","."],

["6",".",".","1","9","5",".",".","."],

[".","9","8",".",".",".",".","6","."],

["8",".",".",".","6",".",".",".","3"],

["4",".",".","8",".","3",".",".","1"],

["7",".",".",".","2",".",".",".","6"],

[".","6",".",".",".",".","2","8","."],

[".",".",".","4","1","9",".",".","5"],

[".",".",".",".","8",".",".","7","9"]

]輸出: false

解釋: 除了第一行的第乙個數字從 5 改為 8 以外,空格內其他數字均與 示例1 相同。

但由於位於左上角的 3x3 宮內有兩個 8 存在, 因此這個數獨是無效的。

說明:

乙個有效的數獨(部分已被填充)不一定是可解的。

只需要根據以上規則,驗證已經填入的數字是否有效即可。

給定數獨序列只包含數字 1-9 和字元 '.' 。

給定數獨永遠是 9x9 形式的。

?我不會

大神的**:

dic_row = [{},{},{},{},{},{},{},{},{}]

dic_col = [{},{},{},{},{},{},{},{},{}]

dic_box = [{},{},{},{},{},{},{},{},{}]

# 一次遍歷,根據 i、j可知道每個值的位置 屬於哪個3 x 3 , 行、列

for i in range(len(board)):

for j in range(len(board)):

num = board[i][j]

if num == ".":

continue

elif num not in dic_row[i] and num not in dic_col[j] and num not in dic_box[3 *(i//3) + (j//3)]:

dic_row[i][num] = 1

dic_col[j][num] = 1

dic_box[3 *(i//3) + (j // 3)][num] = 1

else:

return false

return true

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