python版本：3 若有錯誤，
敬請指出 模組名稱：測試.py
#加分習題38
states =
cities =
cities['ny'] = 'new york'
cities['or'] = 'portland'
print('-'*10,'1')
print("ny stae has:",cities['ny'])
print("or state has:",cities['or'])
print('-'*10,'2')
print("michigan's abbreviation is:",states['michigan'])
print("florida's abbreviation is:",states['florida'])
print('-'*10,'3')
print("michigan has:",cities[states['michigan']])
print("florida has:",cities[states['florida']])
print('-'*10,'4')
for state,abbrev in states.items():
print("%s is abbreviated %s"% (state,abbrev))
print('-'*10,'5')
for abbrev,city in cities.items():
print("%s has the city %s"% (abbrev,city))
print('-'*10,'6')
for state,abbrev in states.items():
print("%s state is abbreviated %s and has city %s"%(state,abbrev,cities[abbrev]))
print('-'*10,'7')
state = states.get('texas',none)
if not state:
print("sorry,no texas")
city = cities.get('tx','does not exist')
print("the city for the state 'tx' is:%s"% city)
print('-'*10,'8')
state = states.get('california',none)
if not state:
print("sorry,no california")
else:
print("да")
#補充：python 字典 get() 函式返回指定鍵的值，如果值不在字典中返回預設值。
#dict.get(key, default=none)
#key -- 字典中要查詢的鍵。
#default -- 如果指定鍵的值不存在時，返回該預設值值。
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