學習shell有一段時間了,一直沒有機會練手,看到同事發了一張**,控制台顯示了當月的日曆,是用python實現的,感覺挺好玩,所以準備用shell來實現乙個,搞了一下午,終於搞定。
列印本月的日期
#! /bin/bash
#設定字型顏色
tiffcolor="\033[0;35m"
menucolor="\033[0;33m"
todaycolor="\033[0;35;44m"
start="\033[0m"
#計算各個日期
month=`date +%m`
day=`date +%d`
year=`date +%y`
weekday=`date -d "$year-$month-01" +%w`
nextmonth=`expr $month + 1`
today=`date +%d`
#計算本月有多少天
differ=$(( ($(date -d "$year-$nextmonth-01" +%s) - $(date +%s))/(24*60*60) ))
days=`expr $differ + $day`
#列印標題
echo -en "$"
echo -en "\t $year $month\n"
echo "sun mon tue wen thu fri sat"
echo -en "$"
#列印空格
if [ $weekday -ne 0 ];then
for((i=1;i<=$weekday;i++))
do echo -n " "
echo -n " "
done
fi#列印日期
for((i=1;i<=$days;i++))
do printf "%s" " "
echo -en "$"
#今天高亮顯示
if [ $today -eq $i ];then
echo -en "$"
fiprintf "%2d" $i
echo -en "$"
echo -en " "
if [ $((($weekday+$i)%7)) == 0 ];then
echo ""
fi# printf "%3d " $i
done
echo ""
執行結果:
擴充套件:給定任意日期,列印當月的日期
#! /bin/bash
#date=$1
tiffcolor="\033[0;35m"
menucolor="\033[0;33m"
todaycolor="\033[0;35;44m"
start="\033[0m"
if [ $# -ne 1 ];then
echo "plz input the date"
exit 1
fidate=$1
count=`echo $date |grep -o '-'|wc -l`
if [ $count -ne 2 ];then
echo "plz input correct date"
exit 1
fiyear=`echo $date|cut -d "-" -f 1`
month=`echo $date|cut -d "-" -f 2`
day=`echo $date|cut -d "-" -f 3`
expr $year + $month + $day + 0 &>/dev/null
if [ $? -ne 0 ];then
echo "plz input a correct date"
exit 1
elif [ $month -gt 12 -o $month -eq 0 ];then
echo "plz input the month between 1 and 12"
exit 1
elif [ $day -gt 31 -o $day -eq 0 ];then
echo "plz input the day between 1 and 31"
1fi#nextmonth=$(( $month + 1))
#month=`date -d "$date" +%m`
#day=`date -d "$date" +%d`
#year=`date -d "$date" +%y`
weekday=`date -d "$year-$month-01" +%w`
if [ $month -eq 12 ];then
newmonth=1
newyear=`expr $year + 1`
else
newyear=$year
#nextmonth= expr $month + 1
newmonth=`expr $month + 1`
fidays=$(( ($(date -d "$-$-01" +%s) - $(date -d "$year-$mo" +%s))/(24*60*60) www.cppcns.com))
#echo $days
echo -en "$"
echo -en "\t $year $month\n程式設計客棧"
echo "sun mon tue wen thu fri sat"
echo -en "$"
if [ $weekday -ne 0 ];then
for((i=1;i<=$weekdawww.cppcns.comy;i++))
do echo -n " "
echo -n " "
done
fifor((i=1;i<=$days;i++))
do printf "%s" " "
echo -en "$"
if [ $day -eq $i ];then
echo -en "$"
fiprintf "%2d" $i
echo -en "$"
echo -en " "
if [ $((($weekday+$i)%7)) == 0 ];then
echo ""
fi# printf "%3d " $i
done
echo ""
執行結果:
本文標題: shell列印給定日期的日曆
本文位址:
查詢給定日期的月份
select substr to char add months to date 200901 yyyymm rownum 1 yyyymm 5,2 月 as month from eos dict entry where add months to date 200901 yyyymm rownu...
將給定日期增加n個月
將給定日期增加numday個月 function adddate dtdate,numday adddate 2008 01 01 replace g,2 adddate 5 5,2004 12 1 00 00 00 function adddate type,numday,dtdate retur...
如何實現給定日期的若干天以後的日期
這幾天突然有很多的人問這樣的問題,就是如何在php中實現在vb中的dateadd的函式,呵呵!這個可是問個正著。本來這個問題是 豆腐 去 華為 應聘的時候的乙個考試題,不過當時是用c 實現的。沒有想到這樣的大公司,竟 然用這樣的小兒科來考試 後來我沒有去,這兩天 應 的 運氣,用php重新 寫了這個...