解決方案有很多，以下來一一例舉
方法一：使用陣列的join()
let arr = [1, 2, 3, 4, 5, [6, 7, 8, [9, 10, 11, 12, [13, 14, 15, 16]]]]
console.log(arr.join()) // 輸出為：1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16
let newarr = arr.join().split(',')
console.log(newarr) // 輸出為：["1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12", "13", "14", "15", "16"]
方法二：使用tostring()方法
let arr = [1, 2, 3, 4, 5, [6, 7, 8, [9, 10, 11, 12, [13, 14, 15, 16]]]]
console.log(arr.tostring()) // 輸出為：1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16
let newarr = arr.tostring().split(',')
console.log(newarr) // 輸出為：["1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12", "13", "14", "15", "16"]
方法三： 使用空字串的方法
let arr = [1, 2, 3, 4, 5, [6, 7, 8, [9, 10, 11, 12, [13, 14, 15, 16]]]]
console.log(arr+ '') // 輸出為：1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16
let newarr = (arr+ '').split(',')
console.log(newarr) // 輸出為：["1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12", "13", "14", "15", "16"]
方法四：遞迴呼叫
let arr = [1, 2, 3, 4, 5, [6, 7, 8, [9, 10, 11, 12, [13, 14, 15, 16]]]]
let newarr = // 存放轉化後的一維陣列
function arrconversion (arr) else {
newarr.push(arr[i])
arrconversion(arr)
console.log(newarr) // 輸出為：["1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12", "13", "14", "15", "16"]
es6寫法
const deepflatten = arr => .concat(...arr.map(v => (array.isarray(v) ? deepflatten(v) : v)));
deepflatten([1, [2], [[3], 4], 5]); // [1,2,3,4,5]
方法五：flat()
console.log([1 ,[2, 3]].flat()); // [1, 2, 3]
// 指定轉換的巢狀層數
console.log([1, [2, [3, [4, 5]]]].flat(2)); // [1, 2, 3, [4, 5]]
// 不管巢狀多少層
console.log([1, [2, [3, [4, 5]]]].flat(infinity)); // [1, 2, 3, 4, 5]
// 自動跳過空位
console.log([1, [2, , 3]].flat());// [1, 2, 3]
方法六： 正則
let ary = [1, [2, [3, [4, 5]]], 6];
let str = json.stringify(ary);
let result = str.replace(/(\[|\])/g, '').split(',');
console.log(result)
方法七： 擴充套件運算子
let ary = [1, [2, [3, [4, 5]]], 6];// -> [1, 2, 3, 4, 5, 6]
//只要有乙個元素有陣列，那麼迴圈繼續
while (ary.some(array.isarray())) {
ary = .concat(...ary);
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