用結構體做的 470+ms;
1 #include 2 #include 3 #include 4 #include 5 #include 6 #include 7 #include 89using
namespace
std;
1011
structn12
;1617struct n *creat()
1824
25int st[50010
];26
27int change(int z,int y,struct n *root)
2837 root->l =creat();
38 root->r =creat();
39int tl = change(z,m,root->l);
40int tr = change(m+1,y,root->r);
41 root->data = (tl +tr);
42return root->data;43}
4445
void add(int site,int s,int z,int y,struct n *root)
4654
55if(site <=m)
5660
else
6165}66
67void sub(int site,int s,int z,int y,struct n *root)
6876
77if(site <=m)
7882
else
8387}88
89int query(int ml,int mr,int z,int y,struct n *root)
90100
else
if(m+1
<=ml)
101104
else
105108
}109
110int
main()
111124
struct n *root =creat();
125126 root->z = 1
;127 root->y =n;
128129 change(1
,n,root);
130131 printf("
case %d:\n
",++icase);
132133
while(scanf("
%s",order) !=eof)
134143
else
if(order[0] == 's'
)144
149else
if(order[0] == 'q'
)150
156}
157158
}159
return0;
160 }
1 #include //用陣列模擬的線段樹 跑了370+ 瑪德 說好的0ms呢2 #include //在大白書 點修改 上看的 就是在不停的傳遞 樹的節點編號node
3 #include //當前節點的左子節點編號為2*node 右子節點為2*node+1;
4 #include 5 #include 6 #include 7 #include 8
9using
namespace
std;
1011
int st[100010
];12
int a[50001
];13
14int change(int node,int l,int
r)15
22 st[node] = change(node+node,l,m) + change(node+node+1,m+1
,r);
23return
st[node];24}
2526
void add(int site,int s,int node,int l,int
r)27
35if(site <=m)
3641
if(m 4247}48
49void sub(int site,int s,int node,int l,int
r)50
58if(site <=m)
5964
if(m 6570}71
72int query(int ml,int mr,int node,int l,int
r)73
78int m = (l+r)/2;79
80if(mr <=m)
8184
if(m 8588
return (query(ml,m,node+node,l,m) + query(m+1,mr,node+node+1,m+1
,r));89}
9091
intmain()
92115
else
if(order[0] == 's'
)116
121else
if(order[0] == 'q'
)122
127else
if(order[0] == 'e'
)128
break
;129
}130
131}
132return0;
133 }
hdu 1166 敵兵布陣
這是一道線段樹里最簡單的一類題目了,單點更新型別!include define lson l m rt 1 define rson m 1 r rt 1 1 const int maxx 55555 int sum maxx 2 void pushup int rt void build int l...
hdu 1166 敵兵布陣
線段樹的模版 沒什麼思想 include include include include include include include include include include include include include define ll long long define vi vec...
HDU 1166 敵兵布陣
description lily 特別喜歡養花,但是由於她的花特別多,所以照料這些花就變得不太容易。她把她的花依次排成一行,每盆花都有乙個美觀值。如果lily把某盆花照料的好的話,這盆花的美觀值就會上公升,如果照料的不好的話,這盆花的美觀值就會下降。有時,lily想知道某段連續的花的美觀值之和是多少...