請你實現乙個類 subrectanglequeries ，它的建構函式的引數是乙個 rows x cols 的矩形（這裡用整數矩陣表示），並支援以下兩種操作：
1. updatesubrectangle(int row1, int col1, int row2, int col2, int newvalue)
用 newvalue 更新以 (row1,col1) 為左上角且以 (row2,col2) 為右下角的子矩形。
2. getvalue(int row, int col)
返回矩形中座標 (row,col) 的當前值。
示例 1：
輸入：["subrectanglequeries","getvalue","updatesubrectangle","getvalue","getvalue","updatesubrectangle","getvalue","getvalue"]
[[[[1,2,1],[4,3,4],[3,2,1],[1,1,1]]],[0,2],[0,0,3,2,5],[0,2],[3,1],[3,0,3,2,10],[3,1],[0,2]]
輸出：[null,1,null,5,5,null,10,5]
解釋：subrectanglequeries subrectanglequeries = new subrectanglequeries([[1,2,1],[4,3,4],[3,2,1],[1,1,1]]);
// 初始的 (4x3) 矩形如下：
// 1 2 1
// 4 3 4
// 3 2 1
// 1 1 1
subrectanglequeries.getvalue(0, 2); // 返回 1
subrectanglequeries.updatesubrectangle(0, 0, 3, 2, 5);
// 此次更新後矩形變為：
// 5 5 5
// 5 5 5
// 5 5 5
// 5 5 5
subrectanglequeries.getvalue(0, 2); // 返回 5
subrectanglequeries.getvalue(3, 1); // 返回 5
subrectanglequeries.updatesubrectangle(3, 0, 3, 2, 10);
// 此次更新後矩形變為：
// 5 5 5
// 5 5 5
// 5 5 5
// 10 10 10
subrectanglequeries.getvalue(3, 1); // 返回 10
subrectanglequeries.getvalue(0, 2); // 返回 5
示例 2：
輸入：["subrectanglequeries","getvalue","updatesubrectangle","getvalue","getvalue","updatesubrectangle","getvalue"]
[[[[1,1,1],[2,2,2],[3,3,3]]],[0,0],[0,0,2,2,100],[0,0],[2,2],[1,1,2,2,20],[2,2]]
輸出：[null,1,null,100,100,null,20]
解釋：subrectanglequeries subrectanglequeries = new subrectanglequeries([[1,1,1],[2,2,2],[3,3,3]]);
subrectanglequeries.getvalue(0, 0); // 返回 1
subrectanglequeries.updatesubrectangle(0, 0, 2, 2, 100);
subrectanglequeries.getvalue(0, 0); // 返回 100
subrectanglequeries.getvalue(2, 2); // 返回 100
subrectanglequeries.updatesubrectangle(1, 1, 2, 2, 20);
subrectanglequeries.getvalue(2, 2); // 返回 20
最多有 500 次updatesubrectangle 和 getvalue 操作。
1 <= rows, cols <= 100
rows == rectangle.length
cols == rectangle[i].length
0 <= row1 <= row2 < rows
0 <= col1 <= col2 < cols
1 <= newvalue, rectangle[i][j] <= 10^9
0 <= row < rows
0 <= col < cols
classsubrectanglequeries:
def__init__
(self, rectangle: list[list[int]]):
self.data=rectangle
self.update=
def updatesubrectangle(self, row1: int, col1: int, row2: int, col2: int, newvalue: int) ->none:
def getvalue(self, row: int, col: int) ->int:
res=none
for i in range(len(self.update)-1,-1,-1):
row1,col1,row2,col2,value=self.update[i]
if row1<=row<=row2 and col1<=col<=col2:
res=value
break
return res if res else
self.data[row][col]
#your subrectanglequeries object will be instantiated and called as such:
#obj = subrectanglequeries(rectangle)
#obj.updatesubrectangle(row1,col1,row2,col2,newvalue)
#param_2 = obj.getvalue(row,col)
1476 子矩形查詢 2020 9 23
請你實現乙個類 subrectanglequeries 它的建構函式的引數是乙個 rows x cols 的矩形 這裡用整數矩陣表示 並支援以下兩種操作 updatesubrectangle int row1,int col1,int row2,int col2,int newvalue 用 new...
陣列 1476 子矩形查詢
1.暴力法 class subrectanglequeries object def init self,rectangle type rectangle list list int self.data rectangle def updatesubrectangle self,row1,col1,...
hihocoder 1476 矩形計數
顯然就是容斥原理了。先算出所有的矩陣一共有多少個 ll sum n n 1 2 m m 1 2 然後考慮對於任取x個黑色方框，他們組成乙個新的矩形，然後計算有多少個矩陣會覆蓋整個矩形，也即，兩條邊所夾住的對頂兩個小正方形的所有點的乘積 奇減偶加即可 include using namespace s...