複雜鍊錶的複製 important

2022-04-17 06:21:15 字數 1224 閱讀 7223

題目描述

輸入乙個複雜鍊錶(每個節點中有節點值,以及兩個指標,乙個指向下乙個節點,另乙個特殊指標指向任意乙個節點),返回結果為複製後複雜鍊錶的head。(注意,輸出結果中請不要返回引數中的節點引用,否則判題程式會直接返回空)

python solution:

# -*- coding:utf-8 -*-

class randomlistnode:

def __init__(self, x):

self.label = x

self.next = none

self.random = none

class solution:

# 返回 randomlistnode

def clone(self, phead):

if phead is none:

return none

current = phead

#在原來的結點之後複製每個結點

while current is not none:

newnode = randomlistnode(current.label)

nextnode = current.next

current.next = newnode

newnode.next = nextnode

current = nextnode

current = phead

#重新遍歷鍊錶給隨機指標賦值

while current is not none:

if current.random is not none:

current.next.random = current.random.next

current = current.next.next

#拆分鍊錶,將鍊錶拆分為原鍊錶和複製後的鍊錶

current = phead

newhead = phead.next

while current is not none:

clonenode = current.next

current.next = clonenode.next

if clonenode.next is not none:

clonenode.next = clonenode.next.next

current = current.next

return newhead

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