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1 #!/bin/bash除錯的時候直接用了2#arglist.h
3 #2012-06-14
45 e_badargs=6567
if [ ! -n "$1"
]8then
9echo
"usage: `basename $0` argument1 argument2 etc."10
exit $e_badargs
11fi
12echo
1314 index=1
15#注意
16echo
"listing args with \"\$*\":"17
for arg in"$*
" # ""
18do
19echo
"arg #$index = $arg
"20 let "
index+=1"21
done
2223
echo
"entire arg list seen as single word."24
echo
2526 index=1
2728
echo
"listing args with\"\$@\":"29
for arg in"$@
"30do31
echo
"arg #$index = $arg
"32 let "
index+=1"33
done
34echo
"arg list seen as seperate words."35
36echo
3738 index=1
39echo
"listing args with \$* (unquoted):"40
for arg in $*
41do
42echo
"arg #$index = $arg
"43 let "
index+=1"44
done
45echo
"arg list seen as separate words.
"46 exit 0
sh -x arglist.sh t1 t2 t3 t4 t5 t6 t7結果就悲催了:
+ e_badargs=65+ [ ! -n t1 ]
+ echo
+ index=1
+ echo listing args with "$*"
:listing args with "$*
":+ echo arg #1 =t1 t2 t3 t4 t5 t6 t7
arg #
1 =t1 t2 t3 t4 t5 t6 t7
+ let index+=1
arglist.
sh: 20: arglist.sh
: let: not found
+ echo
entire arg list seen as single word.
entire arg list seen as single word.
+ echo
+ index=1
+ echo listing args with"$@"
:listing args with"$@
":+ echo arg #1 =t1
arg #
1 =t1
+ let index+=1
arglist.
sh: 32: arglist.sh
: let: not found
+ echo arg #1 =t2
arg #
1 =t2
+ let index+=1
arglist.
sh: 32: arglist.sh
: let: not found
+ echo arg #1 =t3
arg #
1 =t3
+ let index+=1
arglist.
sh: 32: arglist.sh
: let: not found
+ echo arg #1 =t4
arg #
1 =t4
+ let index+=1
arglist.
sh: 32: arglist.sh
: let: not found
+ echo arg #1 =t5
arg #
1 =t5
+ let index+=1
arglist.
sh: 32: arglist.sh
: let: not found
+ echo arg #1 =t6
arg #
1 =t6
+ let index+=1
arglist.
sh: 32: arglist.sh
: let: not found
+ echo arg #1 =t7
arg #
1 =t7
+ let index+=1
arglist.
sh: 32: arglist.sh
: let: not found
+ echo
arg list seen as seperate words.
arg list seen as seperate words.
+ echo
+ index=1
+ echo listing args with $*(unquoted):
listing args with $*(unquoted):
+ echo arg #1 =t1
arg #
1 =t1
+ let index+=1
arglist.
sh: 43: arglist.sh
: let: not found
+ echo arg #1 =t2
arg #
1 =t2
+ let index+=1
arglist.
sh: 43: arglist.sh
: let: not found
+ echo arg #1 =t3
arg #
1 =t3
+ let index+=1
arglist.
sh: 43: arglist.sh
: let: not found
+ echo arg #1 =t4
arg #
1 =t4
+ let index+=1
arglist.
sh: 43: arglist.sh
: let: not found
+ echo arg #1 =t5
arg #
1 =t5
+ let index+=1
arglist.
sh: 43: arglist.sh
: let: not found
+ echo arg #1 =t6
arg #
1 =t6
+ let index+=1
arglist.
sh: 43: arglist.sh
: let: not found
+ echo arg #1 =t7
arg #
1 =t7
+ let index+=1
arglist.
sh: 43: arglist.sh
: let: not found
+ echo
arg list seen as separate words.
arg list seen as separate words.
+ exit 0
/bin/sh指向了dash而不是bash,dash不支援let命令。所以改用,
bash -x arglist.sh t1 t2 t3 t4 t5 t6 t7結果就ok了,若非是用sh -x,還遇不到這個小問題,呵呵。
很水的東東,私錄一下。
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