查詢某一段時間，a在小於五秒鐘內出現2次以上
查詢 某一段時間，a在小於五秒鐘內出現2次以上
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with t as (
select t.a,t.b
from c_table t
where 1 = 1
and b>= to_date('2012-5-29 00:00:00', 'yyyy-mm-dd hh24:mi:ss')
and b<= to_date('2012-5-30 00:00:00', 'yyyy-mm-dd hh24:mi:ss') and t.a>'0' order by t.a )
select t.* from t where exists(
select 1 from t a where t.a=a.a and
abs(t.b-a.b)<=5/(24*60*60) and abs(t.b-a.b)>0 )
--表資訊 www.2cto.com
連鎖店編號 會員卡號 錄入員工號 錄入終端 錄入時間
2012001001 12345678 2012000001 00000001 20120510 16:29:23
2012001001 12345678 2012000001 00000001 20120510 16:30:44
2012001001 12345678 2012000001 00000001 20120510 16:39:12
2012001004 12345678 2012000002 00000001 20120510 16:41:21
2012001004 32345678 2012000002 00000002 20120510 16:43:56
2012001004 22345678 2012000002 00000001 20120510 16:46:49
2012001004 52345678 2012000002 00000002 20120510 16:47:23
2012001001 32345678 2012000003 00000001 20120510 16:49:10
2012001002 82345678 2012000003 00000002 20120510 16:53:08
2012001004 92345678 2012000003 00000003 20120510 16:57:00
2012001005 92345678 2012000003 00000002 20120510 17:01:51
2012001003 82345678 2012000003 00000003 20120510 17:02:23
查詢 同一連鎖店當日同一會員卡號，在相同的終端連續2次以上（含2次）錄入時間=<2分鐘
with t as (
select
'2012001001' a,'12345678' b,'2012000001' c,'1' d,to_date('20120510162923','yyyymmddhh24miss') e from dual union all select
'2012001001','12345678','2012000001','1',to_date('20120510163044','yyyymmddhh24miss') from dual union all select
'2012001001','12345678','2012000001','1',to_date('20120510163912','yyyymmddhh24miss')from dual union all select
'2012001004','12345678','2012000002','1',to_date('20120510164121','yyyymmddhh24miss')from dual union all select
'2012001004','32345678','2012000002','2',to_date('20120510164356','yyyymmddhh24miss')from dual union all select
'2012001004','22345678','2012000002','1',to_date('20120510164649','yyyymmddhh24miss')from dual union all select
'2012001004','52345678','2012000002','2',to_date('20120510164723','yyyymmddhh24miss')from dual union all select
'2012001001','32345678','2012000003','1',to_date('20120510164910','yyyymmddhh24miss')from dual union all select
'2012001002','82345678','2012000003','2',to_date('20120510165308','yyyymmddhh24miss')from dual union all select
'2012001004','92345678','2012000003','3',to_date('20120510165700','yyyymmddhh24miss')from dual union all select
'2012001005','92345678','2012000003','2',to_date('20120510170151','yyyymmddhh24miss')from dual union all select
'2012001003','82345678','2012000003','3',to_date('20120510170223','yyyymmddhh24miss') from dual )
select t.* from t where exists(
select 1 from t a where t.a=a.a and t.b=a.b and t.d= a.d
and abs(t.e-a.e)<=2/(24*60) and abs(t.e-a.e)>0 )
---------------------------------
2012001001 12345678 2012000001 1 2012-5-10 16:29:23
2012001001 12345678 2012000001 1 2012-5-10 16:30:44
/* oracle 時間相減為天數：
select( to_date('20120510162923','yyyymmddhh24miss') - to_date('20120510163044','yyyymmddhh24miss'))*24 *60 *60 from dual
結果為天數：-0.0009375 天
化為分鐘：-0.0009375 * 24 *60 = -1.35 分鐘
化為秒：-1.35 分鐘= -1.35 * 60 = -81秒
*/
某一段時間，在小於五秒鐘內出現2次以上
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