表名:student
建立表:(primary key:主鍵;auto_increment:自動遞增)
create table student
( stuid int primary key auto_increment,
stuname varchar(40) not null
);
插入資料:(因為寫了主鍵遞增,所有stuid=10的後面是stuid=11)
insert into student(stuname) value('zhangsan');
insert into student value(2,'lisi');
insert into student value(10,'wangwu');
insert into student(stuname) value('maliu');
新增列:age (int型別)
alter table student add age int;
更新age列的內容(即根據stuid=xx時,向age裡面新增多大的數)
update student set age=16 where stuid=1;
update student set age=16 where stuid=2;
update student set age=17 where stuid=10;
update student set age=16 where stuid=11;
新增刪除唯一約束:
alter table student add constraint un_name unique(stuname);
alter table student drop index un_name;
增加列:chinese (語文)
alter table student add chinese int;
更新chinese列的內容(即根據stuid=xx時,向chinese裡面新增多大的數)
update student set chinese=122 where stuid=1;
update student set chinese=113 where stuid=2;
update student set chinese=108 where stuid=10;
update student set chinese=98 where stuid=11;
增加列:mathematics (數學)
alter table student add mathematics int;
更新mathematics 列的內容(即根據stuid=xx時,向mathematics 裡面新增多大的數)
update student set mathematics=78 where stuid=1;
update student set mathematics=99 where stuid=2;
update student set mathematics=137 where stuid=10;
update student set mathematics=126 where stuid=11;
增加列:english (英語)
alter table student add english int;
更新english列的內容(即根據stuid=xx時,向english裡面新增多大的數)
update student set english=68 where stuid=1;
update student set english=89 where stuid=2;
update student set english=92 where stuid=10;
update student set english=101 where stuid=11;
增加列:sum(和)
alter table student add sum int;
刪除列:sum(和)
alter table student drop sum;
增加列:stusum(和)
alter table student add stusum int;
求每個人的總分和:
select sum(chinese+mathematics+english) from student where stuid=1;
update student set stusum=(chinese+mathematics+english) where stuid=1;
update student set stusum=(chinese+mathematics+english) where stuid=2;
update student set stusum=(chinese+mathematics+english) where stuid=10;
update student set stusum=(chinese+mathematics+english) where stuid=11;
排序:公升序為asc 降序為desc:
select * from student order by stusum desc;
日期獲取:
select now();
更新日期:
update student set stutime=now() where stuid=1;
update student set stutime=now() where stuid=2;
update student set stutime=now() where stuid=10;
update student set stutime=now() where stuid=11;
字串函式:ascii(返回stuname欄位的第乙個字母的ascii碼):
select ascii(stuname) as numcodeoffirstchar from student;
函式:char_length(s):返回字串 wbn的字元數:
select char_length("wbn") as lengthofstring;
函式:character_length(s):返回字串 wbn的字元數:
select character_length("wbn") as lengthofstring;
函式:concat(s1,s2…sn):合併多個字串:
select concat("sql ", "runoob ", "gooogle ", "facebook") as concatenatedstring;
函式:concat_ws(x, s1,s2…sn):合併多個字串,並新增分隔符:
select concat_ws("-", "sql", "tutorial", "is", "fun!")as concatenatedstring;
函式:field(s,s1,s2…):返回第乙個字串 s 在字串列表(s1,s2…)中的位置:
select field("c", "a", "b", "c", "d", "e");//c在abcde中的位置,3
函式:find_in_set(s1,s2):返回在字串s2中與s1匹配的字串的位置:
select find_in_set("c", "a,b,c,d,e");
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