use j2005_db;
set foreign_key_checks = off;
drop table if exists department;
create table department
(`id` int auto_increment comment '部門id',
`name` varchar(15) comment '部門名稱',
`location` varchar(13) comment '部門所在地',
primary key (id)
) engine = innodb
comment '部門資訊表';
drop table if exists employee;
create table employee
(`id` int auto_increment comment '員工id',
`name` varchar(16) comment '員工姓名',
`job` varchar(16) comment '員工崗位名稱',
`manager_id` int comment '員工上級領導編號',
`hire_date` date comment '入職日期',
`salary` int comment '工資',
`commission` int comment '佣金/獎金',
`department_id` int comment '所屬部門編號',
primary key (id)
) engine = innodb
comment '雇員資訊表';
# alter table employee drop foreign key fk_employee_department_id
alter table employee
add constraint fk_employee_department_id
foreign key employee(department_id)
references department(id);
insert into department values
(1, 'accounting', 'new york'),
(2, 'research', 'dallas'),
(3, 'sales', 'chicago'),
(4, 'operations', 'boston');
insert into employee values
(1, 'smith', 'clerk', 13, '1980-12-17', 800, null, 2),
(2, 'allen', 'salesman', 6, '1981-02-20', 1600, 300, 3),
(3, 'ward', 'salesman', 6, '1981-02-22', 1250, 500, 3),
(4, 'jones', 'manager', 9, '1981-04-02', 2975, null, 2),
(5, 'martin', 'salesman', 6, '1981-09-28', 1250, 1400, 3),
(6, 'blake', 'manager', 9, '1981-05-01', 2850, null, 3),
(7, 'clark', 'manager', 9, '1981-06-09', 2450, null, 1),
(8, 'scott', 'analyst', 4, '1987-07-13', 3000, null, 2),
(9, 'king', 'president', null, '1981-11-17', 5000, null, 1),
(10, 'turner', 'salesman', 6, '1981-09-08', 1500, null, 3),
(11, 'adams', 'clerk', 8, '1987-07-13', 1100, null, 2),
(12, 'james', 'clerk', 6, '1981-12-03', 950, null, 3),
(13, 'ford', 'analyst', 4, '1981-12-03', 3000, null, 2),
(14, 'miller', 'clerk', 7, '1982-01-23', 1300, null, 1);
set foreign_key_checks = on;
-- --------------------------------
檢視兩張表的資訊
select * from department;
select * from employee;
-- ------------------------------------
-- 1. 查詢所有員工資訊
select * from employee;
-- 2. 查詢指定的字段，只查詢姓名和工資
select name,salary from employee;
-- 3. 查詢smith的所有資訊
select * from employee where name='smith';
-- 4. 查詢工資在800-1500之間的員工所有資訊
select * from employee where salary between 800 and 1500;
select * from employee where salary >= 800 and salary <= 1500;
-- 5. 統計一共有多種職業
select count(distinct job) 多種職業 from employee;
-- 6. 使用 as 給表或者列取別名
-- 7. 求出所有員工的總工資(總工資=月薪+獎金)
select salary+ifnull(commission,0) 總工資 from employee
-- ifnull(引數1,引數2) 若引數1為null 使用引數2代替
-- 8. 查詢出前5條員工的資訊
select * from employee where id<=5 order by id;
select * from employee order by id limit 0,5;
-- 9. 查詢出有獎金的員工的姓名、職位、工資
select name,job,salary from employee where commission is not null;
-- 10. where 子句，設定查詢條件
-- 101- 查詢工資大於1000的員工資訊
select * from employee where salary>1000;
-- 102- 查詢不是salesman的員工資訊
select * from employee where job !='salesman';
-- 103- 查詢not between...and查詢工資不在 1000-2000之間的員工資訊
select * from employee where salary not between 1000 and 2000;
-- 104- 模糊查詢，查詢出最後1個字母為s的員工資訊
select * from employee where name like '%s';
-- 105- and > or > not
-- and 所有條件都必須滿足 or 只有有1個條件滿足 not 取反
-- 11. 按照員工的工資進行降序排序，再按照入職時間進行公升序排序
select * from employee order by salary desc,hire_date asc;
-- 12. 按照部門編號進行分組，統計每個部門的員工人數
select department_id 部門編號,count(*) 員工人數 from employee group by department_id
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