ac自動機模板題,判斷各個串分別出現多少次
#include
#include
#include
using
namespace std;
const
int n =
5e4+5;
const
int m =
2e6+5;
const
int c =
1e4+5;
int trie[n]
[128];
//字典樹
int cntword[n]
;//記錄該單詞出現次數
int fail[n]
;//失敗時的回溯指標
int num[n]
;int flag[c]
;int cnt[c]
;int tot =0;
char s[m]
, ss[c][55
];void
insertwords
(char
*s,int l,
int t)
++cntword[root]
;//當前節點單詞數+1
num[root]
= t;
}void
getfail()
}//fail[now] ->當前節點now的失敗指標指向的地方
tire[now][i] -> 下乙個字母為i+'a'的節點的下標為tire[now][i]
while
(!q.
empty()
)else
//否則就讓當前節點的這個子節點
//指向當前節點fail指標的這個子節點
trie[now]
[i]= trie[fail[now]
][i];}
}}void
query
(char
*s,int l)}}
}void
init()
intmain()
fail[0]
=0;getfail()
;scanf
("%s"
, s)
;query
(s,strlen
(s))
;for
(int i =
1; i < c;
++i)
}memset
(trie,0,
sizeof
(trie));
memset
(cntword,0,
sizeof
(cntword));
memset
(flag,0,
sizeof
(flag));
memset
(cnt,0,
sizeof
(cnt));
tot =0;
}return0;
}
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