牛客網 資料庫SQL實戰10

獲取所有非manager的員工emp_no

create

table
`dept_manager`
(`dept_no`
char(4
)not
null
,`emp_no`
int(11)
notnull
,`from_date`
date
notnull
,`to_date`
date
notnull
,primary
key(
`emp_no`
,`dept_no`))
;create
table
`employees`
(`emp_no`
int(11)
notnull
,`birth_date`
date
notnull
,`first_name`
varchar(14
)not
null
,`last_name`
varchar(16
)not
null
,`gender`
char(1
)not
null
,`hire_date`
date
notnull
,primary
key(
`emp_no`))
;

insert

into dept_manager values
('d001'
,10002
,'1996-08-03'
,'9999-01-01');
insert
into dept_manager values
('d002'
,10006
,'1990-08-05'
,'9999-01-01');
insert
into dept_manager values
('d003'
,10005
,'1989-09-12'
,'9999-01-01');
insert
into dept_manager values
('d004'
,10004
,'1986-12-01'
,'9999-01-01');
insert
into dept_manager values
('d005'
,10010
,'1996-11-24'
,'2000-06-26');
insert
into dept_manager values
('d006'
,10010
,'2000-06-26'
,'9999-01-01');
insert
into employees values
(10001
,'1953-09-02'
,'georgi'
,'facello'
,'m'
,'1986-06-26');
insert
into employees values
(10002
,'1964-06-02'
,'bezalel'
,'simmel'
,'f'
,'1985-11-21');
insert
into employees values
(10003
,'1959-12-03'
,'parto'
,'bamford'
,'m'
,'1986-08-28');
insert
into employees values
(10004
,'1954-05-01'
,'chirstian'
,'koblick'
,'m'
,'1986-12-01');
insert
into employees values
(10005
,'1955-01-21'
,'kyoichi'
,'maliniak'
,'m'
,'1989-09-12');
insert
into employees values
(10006
,'1953-04-20'
,'anneke'
,'preusig'
,'f'
,'1989-06-02');
insert
into employees values
(10007
,'1957-05-23'
,'tzvetan'
,'zielinski'
,'f'
,'1989-02-10');
insert
into employees values
(10008
,'1958-02-19'
,'saniya'
,'kalloufi'
,'m'
,'1994-09-15');
insert
into employees values
(10009
,'1952-04-19'
,'sumant'
,'peac'
,'f'
,'1985-02-18');
insert
into employees values
(10010
,'1963-06-01'
,'duangkaew'
,'piveteau'
,'f'
,'1989-08-24');
insert
into employees values
(10011
,'1953-11-07'
,'mary'
,'sluis'
,'f'
,'1990-01-22'
);

無輸出描述:

用子查詢對select檢索出的表項進行篩選，可以用not in 和 not exists兩種方式

select emp_no

from employees
where emp_no notin(
select emp_no
from dept_manager )

select e.emp_no

from employees as e
where
notexists
(select
*from dept_manager as d
where e.emp_no = d.emp_no)
*

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