select name,submittime from enterprise where yearweek(date_format(submittime,'%y-%m-%d')) = yearweek(now());
select name,submittime from enterprise where yearweek(date_format(submittime,'%y-%m-%d')) = yearweek(now())-1;
1）select name,submittime from enterprise where date_format(submittime,'%y-%m')=date_format(now(),'%y-%m')
2）select suggest_id, count(id) as cnt from zhfw_suggest_rank
where read_time >= (date_format(current_date(),'%m')) <= (date_format(current_date(),'%m'))
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
select name,submittime from enterprise where date_format(submittime,'%y-%m')=date_format(date_sub(curdate(), interval 1 month),'%y-%m')
select * from `user` where date_format(pudate,'%y%m') = date_format(curdate(),'%y%m') ;
select * from user where weekofyear(from_unixtime(pudate,'%y-%m-%d')) = weekofyear(now())
select * from user where month(from_unixtime(pudate,'%y-%m-%d')) = month(now())
select * from [user] where year(from_unixtime(pudate,'%y-%m-%d')) = year(now()) and month(from_unixtime(pudate,'%y-%m-%d')) = month(now())
select * from [user] where pudate between 上月最後一天 and 下月第一天
select * from zhfw_service_theme where to_days(created_time) = to_days(now())
select count(*) from `t_view` where datediff(now(),create_time) = 0
select count(*) from `t_view` where datediff(now(),create_time) = 1
select count(*) from `t_view` where datediff(now(),create_time) = 2
多條件查詢比較簡單，即將相應的條件以新增and的形式加在後面，如：
select * from employee
where fnumber between 'dev001' and 'dev008'
and fname like '%j%'
and fsalary between 3000 and 6000
select @rowno := @rowno + 1 as rowno, t.*
from (select t.article_title, t1. name, t.article_createdate
from t_article t
left join t_article_type t1
on t.typeid = t1. name
where t.article_title like '%博士%'
order by article_createdate desc) t,
(select @rowno := 0) t3
order by rowno
select * from tablename limit n,m
//查詢前n行記錄
-- 方法一
select * from table1 limit 0,n;
-- 方法二
select * from table1 limit n;
//查詢後n行記錄
-- 倒序排序，取前n行 id為自增形式
select * from table1 order by id desc dlimit n；
//查詢一條記錄($id)的下一條記錄
select * from table1 where id>$id order by id asc dlimit 1
//查詢一條記錄($id)的上一條記錄
select * from table1 where id<$id order by id desc dlimit 1
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