編譯原理詞法分析程式C 實現

題目要求：對給定的c語言程式，識別出關鍵字、整型常量、實型常量（包括1.23e-23這樣的科學計數法）、識別符號、分隔符、運算子。

語言：c++

整合環境：vs 2017

演算法：使用狀態轉換圖實現

程式**：

/*

關鍵字：；標示符：；整型常量<200,數值》；實型常量<300,數值》；分隔符：<400-408, >；運算子：<500-, >
*/#include
#include
#include
#include
#include
#include
#include
using
namespace std;
struct tuple
;vector constant =
;vector result;
vector<
char
>file_content;
vector keyword =
;vector<
char
>separater =',
'[',
']',
'(',
')'}
;vector<
char
>operators =
;void
getfile
(string file_name)
in_file.
close()
;}bool
isletter
(char c)
bool
isblank
(char c)
bool
isnumber
(char c)
intiskeyword
(string str)
bool
isinteger
(string str)
}int
isseparater
(char c)
bool
isoperator
(char c)
intmatchoperator
(char c)
void
lexicalanalyzer()
if(isletter
(temp_ch)
)int index =
iskeyword
(temp_word)
;			tuple temp_tuple;
if(index!=0)
else
continue;}
if(isnumber
(temp_ch)
)			tuple temp_tuple;
temp_tuple.content = temp_word;if(
isinteger
(temp_word)
)				temp_tuple.val =
"200"
;else
temp_tuple.val =
"300"
;			result.
push_back
(temp_tuple)
;continue;}
if(isseparater
(temp_ch)!=0
)if(isoperator
(temp_ch)
)			tuple temp_tuple;
if(temp_word ==
"++")if
(temp_word ==
"--")if
(temp_word ==
"&&")if
(temp_word ==
"||"
)else
else
}			result.
push_back
(temp_tuple)
;continue;}
i++;}
}void
printresult()
}int
main()

int main()

return 0;
}

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