用c#實現複數的加減乘除
在本文中，我將向您展示一種使用c程式語言實現複數的方法。 請注意，使用此處提供的**沒有任何保證。
複數是乙個數字，例如z，表示z = realpart + i * imaginarypart，其中i是虛數單位，有時用j表示。 另外，i * i = -1，這在找到兩個複數的乘積/除法時很重要。
自然，我們可以將複數實現為結構：
/* definition of a complex number: */
typedef struct complex complex;
首先，我們有標題
complex.h，它定義了complex結構幷包含操作乙個或多個complex數字的函式的原型：
/* complex.h */
#ifndef complex_h
#define complex_h
/* definition of a complex number: */
typedef struct complex complex;
/* prototypes for functions to manipulate complex number(s) (these functions are implemented in file complex.c): */
complex addition( const complex *pointertocomplexnumber1, const complex *pointertocomplexnumber2 );
complex subtraction( const complex *pointertocomplexnumber1, const complex *pointertocomplexnumber2 );
complex multiplication( const complex *pointertocomplexnumber1, const complex *pointertocomplexnumber2 );
complex division( const complex *pointertocomplexnumber1, const complex *pointertocomplexnumber2 );
void print( const complex *pointertocomplexnumber );
#endif
/* complex.c */
#include
#include "complex.h"
/* adds two complex numbers, returning a new one, without modifying the ones received: */
complex addition( const complex *pointertocomplexnumber1, const complex *pointertocomplexnumber2 )
/* subtracts two complex numbers, returning a new one, without modifying the ones received: */
complex subtraction( const complex *pointertocomplexnumber1, const complex *pointertocomplexnumber2 )
/* multiplies two complex numbers, returning a new one, without modifying the ones received: */
complex multiplication( const complex *pointertocomplexnumber1, const complex *pointertocomplexnumber2 )
/* divides two complex numbers, returning a new one, without modifying the ones received: */
complex division( const complex *pointertocomplexnumber1, const complex *pointertocomplexnumber2 )
/* prints a complex number in the form ( realpart ) + i( imaginarypart ), without modifying it: */
void print( const complex *pointertocomplexnumber )
/* complextest.c */
#include
#include "complex.h"
int main( void )
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