通過對運算子過載進行複數簡單運算

對複數的除法運算有瑕疵；如何能在不更改show()函式的情況下使得複數輸出能保留位數輸出。。。。。

#include #include using namespace std;

class complex
double real()
double imag()
complex operator+(const complex &c);
complex operator+(const double &d)
complex operator=(const complex &c);
complex operator-(const complex &c);
complex operator-(const double &d)
complex operator*(const complex &c);
complex operator*(const double &d)
complex operator/(const double &d)
complex operator/(const complex &c);
void show();
};/*
//該法會改變第乙個資料的資料，如c3=c2+c1;用此加法會使c2與c3相等（均是計算後的資料） 
complex complex::operator+(const complex &c)
*///該法不會改變第乙個資料的資料 
complex complex::operator+(const complex &c)
/* //用該法定義賦值行為將不會改變*this的資料 
complex complex::operator=(const complex &c)
*/ complex complex::operator=(const complex &c)
complex complex::operator-(const complex &c)
complex complex::operator*(const complex &c)
complex complex::operator/(const complex &c)
void complex::show()

#include #include using namespace std;

class complex
double real()
double imag()
complex operator+(const complex &c);
complex operator+(const double &d)
complex operator=(const complex &c);
complex operator-(const complex &c);
complex operator-(const double &d)
complex operator*(const complex &c);
complex operator*(const double &d)
complex operator/(const double &d)
complex operator/(const complex &c);
void show();
};/*
//該法會改變第乙個資料的資料，如c3=c2+c1;用此加法會使c2與c3相等（均是計算後的資料） 
complex complex::operator+(const complex &c)
*///該法不會改變第乙個資料的資料 
complex complex::operator+(const complex &c)
/* //用該法定義賦值行為將不會改變*this的資料 
complex complex::operator=(const complex &c)
*/ complex complex::operator=(const complex &c)
complex complex::operator-(const complex &c)
complex complex::operator*(const complex &c)
complex complex::operator/(const complex &c)
void complex::show()
c2.show();
cout<<")=(";
c.show();
cout<<")"
return 0;
}

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