select id from info
id-----------12
3567
8101112
15(11 行受影響)
方法一：
select (select max(id)+1 from info where id(select max(id)+1 from info where idbeginid endid
----------- -----------
4 4
9 9
13 14
(3 行受影響)
方法二：
select beginid,(select min(id)-1 from info where id > beginid) as endid
from (
select id+1 as beginid from info where id+1 not in (select id from info) and id < (select max(id) from info)
) as t
beginid endid
----------- -----------
4 4
9 9
13 14
(3 行受影響)
說明：1、查詢結果的兩列是斷號的區間，如果beginid=endid，則表示缺少該號碼，否則表示缺少beginid ~ endid；
2、如果號碼1不存在，區間1 ~ select min(id)-1 from info 將無法找出
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