把二叉搜尋樹轉化成更大的樹

"""

definition of treenode:
class treenode:
def __init__(self, val):
self.val = val
self.left, self.right = none, none
"""class solution:
"""@param root: the root of binary tree
@return: the new root
"""def __init__(self):
self.lsum = 0
def convertbst(self, root):
# write your code here
if root is  none:
return none
self.convertbst(root.right)# 初始化 lsum為右節點
self.lsum += root.val # 右節點加根節點值
root.val = self.lsum # 把值賦給根節點
self.convertbst(root.left) #遞迴左潔典
return root

given a binary search tree `｀:

5

/   \
2     13

18

/   \
20     13

把二叉搜尋樹轉化成更大的樹

definition of treenode class treenode def init self,val self.val val self.left,self.right none,none class solution param root the root of binary tree ...

BST 把搜尋二叉樹轉化成雙鏈表

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BST 把搜尋二叉樹轉化成雙鏈表

題目 epi 雙鏈表的節點和二叉樹節點類似，left當做前繼節點prev，right當做後繼節點next typedef shared ptr pnode 返回值是pair型別，first是雙鏈表第乙個節點，second是雙鏈表最後乙個節點 paircovert bst to doublelist ...