oracle 分析函式——cube ， rollup
cube
功能描述：
注意：
rollup
功能描述：
注意：
如果是 rollup(a, b, c) 的話， group by 順序
(a 、 b 、 c)
(a 、 b)
(a)
最後對全表進行 group by 操作。
如果是 group by cube(a, b, c) ， group by 順序
(a 、 b 、 c)
(a 、 b)
(a 、 c)
(a) ，
(b 、 c)
(b)
(c) ，
最後對全表進行 group by 操作。
create table studentscore (
student_name varchar2(20),
subjects varchar2(20),
score number )
insert into studentscore values('wbq','english',90);
insert into studentscore values('wbq','maths',95);
insert into studentscore values('wbq','chinese',88);
insert into studentscore values('czh','english',80);
insert into studentscore values('czh','maths',90);
insert into studentscore values('czh','history',92);
insert into studentscore values('cb','politics',70);
insert into studentscore values('cb','history',75);
insert into studentscore values('ldh','politics',80);
insert into studentscore values('ldh','chinese',90);
insert into studentscore values('ldh','history',95);
select
student_name,
subjects,
sum(score)
from studentscore
group by cube(student_name,subjects);
等同於以下標準 sql
select null,subjects,sum(score)
from studentscore
group by subjects
union
select student_name,null,sum(score)
from studentscore
group by student_name
union
select null,null,sum(score)
from studentscore
union
select student_name,subjects,sum(score)
from studentscore
group by student_name,subjects
select
student_name,
subjects,
sum(score)
from studentscore
group by rollup(student_name,subjects);
select student_name,null,sum(score)
from studentscore
group by student_name
union
select null,null,sum(score)
from studentscore
union
select student_name,subjects,sum(score)
from studentscore
group by student_name,subjects
select
grouping(student_name),
grouping(subjects),
student_name,
subjects,
sum(score)
from studentscore
group by cube(student_name,subjects)
order by 1,2;
select
grouping(student_name),
grouping(subjects),
student_name,
subjects,
sum(score)
from studentscore
group by rollup(student_name,subjects)
order by 1,2;
select
grouping_id(student_name,subjects),
student_name,
subjects,
sum(score)
from studentscore
group by cube(student_name,subjects)
order by 1;
select
grouping_id(student_name,subjects),
student_name,
subjects,
sum(score)
from studentscore
group by rollup(student_name,subjects)
order by 1;
select
grouping(student_name),
grouping(subjects),
case when grouping(student_name)=0 and grouping(subjects)=1 then ' 學生成績合計 '
when grouping(student_name)=1 and grouping(subjects)=0 then ' 課目成績合計 '
when grouping(student_name)=1 and grouping(subjects)=1 then ' 總 計 '
else ''
end summary,
student_name,
subjects,
sum(score)
from studentscore
group by cube(student_name,subjects)
order by 1,2;
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