1 根據條件查總數
select
count(*) all_sum, if(sum(if(problem_state in (1,2),1,0)) is null,0,sum(if(problem_state in (1,2),1,0))) problem_num,
if(sum(if(problem_state=3,1,0)) is null,0,sum(if(problem_state=3,1,0))) handled_num
from problem_feedback where
problem_state in (1,2,3) and
date_format(problem_find_time,'%y-%m-%d') = # and
department_id in
#2根據時間計算總數（用在報表柱上）
select hours,sum(count) count ,sum(rank) rank from (
select
case when hour(problem_find_time)in(0,1,2) or null then '0-2點'
when hour(problem_find_time)in(3,4,5) or null then '3-5點'
when hour(problem_find_time)in(6,7,8) or null then '6-8點'
when hour(problem_find_time)in(9,10,11) or null then '9-11點'
when hour(problem_find_time)in(12,13,14) or null then '12-14點'
when hour(problem_find_time)in(15,16,17) or null then '15-17點'
when hour(problem_find_time)in(18,19,20) or null then '18-20點'
when hour(problem_find_time)in(21,22,23) or null then '21-23點'
end as `hours` ,count(hour(problem_find_time)) count,0 as rank
from problem_feedback where
problem_state in
#and
date_format(problem_find_time,'%y-%m-%d') = # and
department_id in
#group by hours
union select '0-2點'hours , 0 count,1 rank
union select '3-5點' hours , 0 count,2 rank
union select '6-8點' hours, 0 count,3 rank
union select '9-11點' hours, 0 count,4 rank
union select '12-14點' hours, 0 count,5 rank
union select '15-17點' hours, 0 count,6 rank
union select '18-20點' hours, 0 count,7 rank
union select '21-23點' hours, 0 count,8 rank
)aagroup by hours
order by rank
3類似的還有周報表
select week,sum(num) num from (
select week ,sum(num) num from(
select weekday(problem_find_time) week,count(problem_find_time) num
from problem_feedback where problem_find_time is not null
andproblem_state in
#and
date_format(problem_find_time,'%y-%m-%d') between # and # and
department_id in
#group by weekday(problem_handle_time)) aa group by week
union
select 0 week,0 num
union
select 1 week,0 num
union
select 2 week,0 num
union
select 3 week,0 num
union
select 4 week,0 num
union
select 5 week,0 num
union
select 6 week,0 num) aa
group by week
4 月報表
select time , sum(num) total from (
select date_format(problem_find_time,'%d') time ,count(problem_find_time) num
from problem_feedback where problem_find_time is not null
andproblem_state in
#and
date_format(problem_find_time,'%y-%m') = # and
department_id in
#group by date_format(problem_find_time,'%y-%m-%d')
union select '01' as time,'0' as sum
union select '02' as time,'0' as sum
union select '03' as time,'0' as sum
union select '04' as time,'0' as sum
union select '05' as time,'0' as sum
union select '06' as time,'0' as sum
union select '07' as time,'0' as sum
union select '08' as time,'0' as sum
union select '09' as time,'0' as sum
union select '10' as time,'0' as sum
union select '11' as time,'0' as sum
union select '12' as time,'0' as sum
union select '13' as time,'0' as sum
union select '14' as time,'0' as sum
union select '15' as time,'0' as sum
union select '16' as time,'0' as sum
union select '17' as time,'0' as sum
union select '18' as time,'0' as sum
union select '19' as time,'0' as sum
union select '20' as time,'0' as sum
union select '21' as time,'0' as sum
union select '22' as time,'0' as sum
union select '23' as time,'0' as sum
union select '24' as time,'0' as sum
union select '25' as time,'0' as sum
union select '26' as time,'0' as sum
union select '27' as time,'0' as sum
union select '28' as time,'0' as sum
union select '29' as time,'0' as sum
union select '30' as time,'0' as sum
union select '31' as time,'0' as sum )aa group by time
這是我們計算報表常用sql
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