oracle分析函式(同比,環比,累計,基比) 分類:
oracle
create table salarybymonth
employeeno varchar2(20),
yearmonth varchar2(6),
salary number
) ;insert into salarybymonth (employeeno, yearmonth, salary)
values (1, '200805', 500);
insert into salarybymonth (employeeno, yearmonth, salary)
values (1, '200802', 150);
insert into salarybymonth (employeeno, yearmonth, salary)
values (1, '200803', 200);
insert into salarybymonth (employeeno, yearmonth, salary)
values (1, '200804', 300);
insert into salarybymonth (employeeno, yearmonth, salary)
values (1, '200708', 100);
commit;
select employeeno
,yearmonth
,salary
,min(salary) keep(dense_rank first order by yearmonth) over(partition by employeeno) first_salary -- 基比分析 salary/first_salary
,lag(salary, 1, 0) over(partition by employeeno order by yearmonth) as prev_sal -- 環比分析,與上個月份進行比較
,lag(salary, 12, 0) over(partition by employeeno order by yearmonth) as prev_12_sal -- 同比分析,與上個年度相同月份進行比較
,sum(salary) over(partition by employeeno, substr(yearmonth, 1, 4) order by yearmonth range unbounded preceding) lj --累計值
from salarybymonth
order by employeeno
,yearmonth
Oracle同比 環比和累計
create table salarybymonth employeeno varchar2 20 yearmonth varchar2 6 salary number insert into salarybymonth employeeno,yearmonth,salary values 1,20...
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