1，leetcodecn上合併兩個有序鍊錶：將兩個有序鍊錶合併為乙個新的有序鍊錶並返回。新煉表是通過拼接給定的兩個鍊錶的所有節點組成的。
示例：輸入：1->2->4, 1->3->4
輸出：1->1->2->3->4->4
def mergetwolists(l1, l2):
head = none
node = head
while l1 != none and l2 != none:
if l1.val < l2.val:
if head == none:
head = l1
node = head
else:
node.next = l1
node = node.next
l1 = l1.next
else:
if head == none:
head = l2
node = head
else:
node.next = l2
node = node.next
l2 = l2.next
if l1 != none:
if head == none:
head = l1
else:
node.next = l1
if l2 != none:
if head == none:
head = l2
else:
node.next = l2
return head
def mergetwolists(self, l1, l2):
prehead = listnode(-1)
prev = prehead
while l1 and l2:
if l1.val <= l2.val:
prev.next = l1
l1 = l1.next
else:
prev.next = l2
l2 = l2.next
prev = prev.next
prev.next = l1 if l1 is not none else l2
return prehead.next
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