group_concat( distinct (if(t_r.id='2','特殊處理',t_r.data) )), t_s.id
解決辦法 order by 乙個id 保證left join有序 如果oder by後的順序依然有等值的就再加個屬性來排序
update t_target t_tar
left
join
(select
ifnull(sum(ifnull(park_state,0)),0)sm, park_id
from
t_park_state
group
by park_id) r_st on r_st.park_id = e_s.park_id
left
join
t_park t_p on t_p.park_id = e_s.park_id
set
t_tar.empty_num = (ifnull(t_p.total_space,0) - ifnull(r_st.sm,0))
delimiter $$
drop procedure if exists add_col_homework;
create procedure add_col_homework()
begin
if not exists ( select
column_name
from
information_schema.columns
where
1 = 1
and table_name ='t_detail_berth_ordinates'
and column_name ='min_berth_number')
then
alter table `t_detail_berth_ordinates` add column `min_berth_number`
varchar(36);
end if;
end;
call add_col_homework;
$$
select inet_aton('192.168.0.0')create
table
`t_user5` (
`id`
int(11) not
null auto_increment,
`name`
varchar(45) collate utf8_unicode_ci default
null,
`updatetime` datetime not
null
default
current_timestamp
onupdate
current_timestamp comment '時間隨時更新',
`createtime` datetime not
null
default
current_timestamp comment '時間是建立的時間，不隨時更新',
primary
key (`id`)
) engine=innodb default charset=utf8 collate=utf8_unicode_ci
insert
into test.t_user (id, name) values("1","tom");
insert
into test.t_user (id, name) values("2","jack");
update test.t_user set name ='june'
where id =2;
select * from test.t_user;
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