mysql查詢日期補全（連續）方法

select

od.date,
od.ordercount
from
(select
date_format(order_time,'%y-%m-%d') date,
count(*) ordercount
from
order
where
order_time>'開始時間'
and order_time<'結束時間'
group
by date_format(order_time,'%y-%m-%d')
union (select
0, '2017-03-01')
union (select
0, '2017-03-02')
union (select
0, '2017-03-03')
union (select
0, '2017-03-04')
union (select
0, '2017-03-05')
union (select
0, '2017-03-06')
union (select
0, '2017-03-07')
union (select
0, '2017-03-08')
-- 很多個union ......
) as od
group
by od.date
order
by od.date
asc如果有日期表那就用聯表就行了，這裡是不聯表的方法，在程式上做處理後拼接到sql上
public function 
getlaidianlaifang
($proj_ids
, $start_date
, $end_date
, $gjfs
, $type
)$where 
= " and proj_id in ('"
.implode(
"','"
, $proj_ids
)."')"
;$rs 
= $this
->
dealdate
($type
, $start_date
, $end_date);
$group 
= $rs
['group'];
$union 
= $rs
['union'];
$sql 
= "select d.gj_cst_sum,d.date_type from (select 
count
(distinct opp_id) as gj_cst_sum,
as date_type from s_opp2gjjl where gjfs = 
and gj_date between :start_date and :end_date 
group by  ) 
as d group by d.date_type order by d.date_type asc"
;return 
$this
->
kfsdb
->
createcommand
($sql, [
':start_date' 
=> 
$start_date
, ':end_date' 
=> 
$end_date
.' 23:59:59'
])->
queryall();
}

/**

* 處理時間，把缺的補上
* */
private function 
dealdate
($type
, $start_date
, $end_date
, $proj 
= null
) )";}
}elseif
($type 
== 3)' 
)";}}
elseif 
($type 
== 4
) )";}
}elseif 
($type 
== 5
) )";}
}return 
['group' 
=> 
$group
, 'union' 
=> 
$union];
}

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