python指令碼傳送普通郵件

2021-07-24 03:28:51 字數 1024 閱讀 4386

#!/usr/bin/python


#coding=utf-8


import smtplib


from email.mime.text import mimetext


from email.header import header


mail_host = "smtp.163.com"


mail_user = "網易賬號@163.com"


mail_pass = "smtp服務密碼"


sender = '網易賬號@163.com'


receivers = ['qq號@qq.com']


#三個引數：第乙個為內容第二個是文字格式第三個是utf-8編碼


message = mimetext('你奈我何', 'plain', 'utf-8')


message['from'] = '網易賬號@163.com'


message['to'] =  'qq號@qq.com'


subject = "凱"


message['subject'] = header(subject, 'utf-8')


try:


smtpobj = smtplib.smtp()


smtpobj.connect(mail_host, 25)    # 25 為 smtp 埠號


smtpobj.ehlo()


smtpobj.starttls()


smtpobj.login(mail_user,mail_pass)


#    i = 1


#    while(i < 10):


smtpobj.sendmail(sender, receivers, message.as_string())


#       i = i + 1


print


"郵件傳送成功"


except smtplib.smtpexception,e:


print


"error: 無法傳送郵件"


print e;

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