先貼**
package com.mult.test;
public class mythread
class runaablethread implements runnable catch (interruptedexception e)
system.out.println(thread.currentthread().getname() + " is selling ticket " + ticketcount);
ticketcount--;
}} }
}
t3 is selling ticket 20
t1 is selling ticket 19
t2 is selling ticket 18
t2 is selling ticket 17
t3 is selling ticket 17
t1 is selling ticket 17
t1 is selling ticket 14
t3 is selling ticket 13
t2 is selling ticket 12
t1 is selling ticket 11
t3 is selling ticket 10
t2 is selling ticket 9
t3 is selling ticket 8
t1 is selling ticket 7
t2 is selling ticket 6
t1 is selling ticket 5
t3 is selling ticket 4
t2 is selling ticket 3
t3 is selling ticket 2
t1 is selling ticket 1
t2 is selling ticket 0
t3 is selling ticket -1
明明設定了＞０的限制條件，為何會賣到0乃至-1?可以推想，當t1**掉最後一張票時，t2和t3已經進入了while迴圈。這是乙個執行緒同步的問題，共享的資源沒有被保護起來，導致t1,t2,t3同時操作去賣最後一張票。起初嘗試的是這樣的**來解決這個問題
package com.mult.test;
public class mythread
class runaablethread implements runnable catch (interruptedexception e)
//if(ticketcount > 0) }}
} }}
發現是不行的：將整個while迴圈用synchronized修飾，最先進入到while的執行緒將會佔據資源，直到賣完20張票：
t1 is selling ticket 20
t1 is selling ticket 19
t1 is selling ticket 18
t1 is selling ticket 17
t1 is selling ticket 16
t1 is selling ticket 15
t1 is selling ticket 14
t1 is selling ticket 13
t1 is selling ticket 12
t1 is selling ticket 11
t1 is selling ticket 10
t1 is selling ticket 9
t1 is selling ticket 8
t1 is selling ticket 7
t1 is selling ticket 6
t1 is selling ticket 5
t1 is selling ticket 4
t1 is selling ticket 3
t1 is selling ticket 2
t1 is selling ticket 1
目前的乙個笨辦法是：
package com.mult.test;
public class mythread
class runaablethread implements runnable catch (interruptedexception e)
synchronized(this) }}
} }}
只保護上面紅字的部分。這樣是可以實現同步賣票的：
t3 is selling ticket 20
t1 is selling ticket 19
t2 is selling ticket 18
t1 is selling ticket 17
t3 is selling ticket 16
t2 is selling ticket 15
t2 is selling ticket 14
t3 is selling ticket 13
t1 is selling ticket 12
t1 is selling ticket 11
t3 is selling ticket 10
t2 is selling ticket 9
t3 is selling ticket 8
t1 is selling ticket 7
t2 is selling ticket 6
t2 is selling ticket 5
t1 is selling ticket 4
t3 is selling ticket 3
t1 is selling ticket 2
t3 is selling ticket 1
不過更好的辦法肯定有，目前正在研究中。
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