--pl/sql顯示哪個使用者(會話sid以及serial)通過什麼工具執行了什麼操作
declare
x number;
begin
for x in
( select username||'('||sid||','||serial#||
') ospid = ' || process ||
' program = ' || program username,
to_char(logon_time,' day hh24:mi') logon_time,
to_char(sysdate,' day hh24:mi') current_time,
sql_address, last_call_et
from v$session
where status = 'active'
and rawtohex(sql_address) <> '00'
and username is not null order by last_call_et )
loop
for y in ( select max(decode(piece,0,sql_text,null)) ||
max(decode(piece,1,sql_text,null)) ||
max(decode(piece,2,sql_text,null)) ||
max(decode(piece,3,sql_text,null))
sql_text
from v$sqltext_with_newlines
where address = x.sql_address
and piece < 4)
loop
if ( y.sql_text not like '%listener.get_cmd%' and
y.sql_text not like '%rawtohex(sql_address)%')
then
dbms_output.put_line( '--------------------' );
dbms_output.put_line( x.username );
dbms_output.put_line( x.logon_time || ' ' ||
x.current_time||
' last et = ' ||
x.last_call_et);
dbms_output.put_line(
substr( y.sql_text, 1, 250 ) );
end if;
end loop;
end loop;
end;
select username||'('||sid||','||serial#||')' username,
module,
action,
client_info
from v$session
where module||action||client_info is not null;
select min(level)
from dual
where nvl(substr('字串1',level,1),' ')<>nvl(substr('字串2',level,1),' ')
connect by level<=200;
--求兩個日期相差多少天、多少小時、多少分、多少秒
select extract(day
from(to_date('2012-12-31 12:11:12', 'yyyy-mm-dd hh24:mi:ss') -
to_date('2012-12-11 11:11:12', 'yyyy-mm-dd hh24:mi:ss'))
day(9) to second) || '天'||
extract(hour
from(to_date('2012-12-31 12:11:12', 'yyyy-mm-dd hh24:mi:ss') -
to_date('2012-12-11 11:11:12', 'yyyy-mm-dd hh24:mi:ss'))
day(9) to second) || '時'||
extract(minute
from(to_date('2012-12-31 12:11:12', 'yyyy-mm-dd hh24:mi:ss') -
to_date('2012-12-11 11:11:12', 'yyyy-mm-dd hh24:mi:ss'))
day(9) to second) || '分鐘'||
extract(second
from(to_date('2012-12-31 12:11:12', 'yyyy-mm-dd hh24:mi:ss') -
to_date('2012-12-11 11:11:12', 'yyyy-mm-dd hh24:mi:ss'))
day(9) to second) || '秒'
from dual
--求指定月內哪天在日曆表是對應哪周.
如:2013.04.01----2013.04.06為第一周,依次類推.
如果直接使用to_char(sysdate,'w')得到的週是按每個月的前7天為第一周的,這樣和日曆表上的有點出入.
select to_date('2013-04-01', 'yyyy-mm-dd') + level - 1,
ceil((to_char(to_date('2013-04-01', 'yyyy-mm-dd'), 'd') + level - 1) / 7) 周
from dual
connect by level <= 30;
--表t11有a,b兩個字段,a欄位為空,b欄位是26個字母無序排列
--要求更新a列,使得b='a'時,a=1;b='b'時,a=2;b='c'時,a=3...
update t11 c
set a =
(select rn
from (select rank() over(order by b) rn, b from t11) d
where d.b = c.b);
12:08:39 sys@orcl> select substr(col12:08:43 2 ,decode(level, 1, 1, instr(col, ',', 1, level - 1) + 1)
12:08:43 3 ,decode(instr(col, ',', 1, level)
12:08:43 4 ,0
12:08:43 5 ,length(col) + 1
12:08:43 6 ,instr(col, ',', 1, level)) -
12:08:43 7 decode(level, 1, 1, instr(col, ',', 1, level - 1) + 1)) col
12:08:43 8 from (select '&a' col from dual)
12:08:43 9 connect by level <= length(translate(col, ',' || col, ',')) + 1;
輸入 a 的值: aa,bb,cc,dd,ee,ff
col----------------------------------
aabb
ccdd
eeff
已選擇6行。
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