if not object_id('today') is null
drop table today
go create table today(id int identity(1,1) primary key,inmoney int,date smalldatetime,name varchar(20))
insert into today
select 500,'2008-5-1','廠家1'
union all select 500,'2008-6-1','廠家2'
union all select 500,'2008-7-1','廠家1'
union all select 500,'2008-5-2','廠家3'
union all select 500,'2008-7-2','廠家2'
union all select 500,'2008-8-1','廠家1'
union all select 500,'2008-6-1','廠家1'
declare @col as varchar(4000),@sql varchar(8000)
set @col = ''
drop table #temp
select distinct [name] into #temp from today
select @col = @col + '[' + [name] + ']=sum(case when [name]='''
+ [name] + ''' then [inmoney] else 0 end),'
from #temp
--方法1：通過case when語法進行crosstab逐項聚合查詢
set @sql = 'select left(convert(varchar,date,20),7) 月份,' + left(@col,len(@col)-1)
set @sql = @sql + ' from today group by left(convert(varchar,date,20),7)'
execute (@sql)
--方法2（sql server 2005以上）：通過pivot來實現
select @col = ''
select @col = @col + 'isnull(sum([' + [name] + ']),0) ' + [name] + ',' from #temp
set @sql = 'select left(convert(varchar,a.date,20),7) 月份,'
+ left(@col,len(@col)-1) + ' from today pivot(sum(inmoney) for name in('
select @col = ''
select @col = @col + '[' + [name] + '],' from #temp
set @sql = @sql + left(@col,len(@col)-1) + ')) as a group by left(convert(varchar,a.date,20),7)'
execute (@sql)
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