python 稀疏陣列的處理

2021-04-25 01:00:12 字數 2820 閱讀 3901

話說python 還真是方便。。 用c要寫n長的** python百行左右就解決了

#!/usr/bin/env python

#-*- coding:utf-8 -*-

#資料結構------------處理稀疏陣列

import copy

def subsparse(dict_sparse_a, dict_sparse_b):

'''兩個字典相減'''

dict_sparse_sub = dict()

for i in dict_sparse_a:

if i in dict_sparse_b:

dict_sparse_sub[i] = dict_sparse_a[i] - dict_sparse_b[i]

else:

dict_sparse_sub[i] = dict_sparse_a[i]

for j in dict_sparse_b:

if j not in dict_sparse_sub:

dict_sparse_sub[j] = 0 - dict_sparse_b[j]

dict_sparse_sub2 = copy.deepcopy(dict_sparse_sub)

for i in dict_sparse_sub:

if dict_sparse_sub[i] == 0:

del dict_sparse_sub2[i]

return dict_sparse_sub2

def addsparse(dict_sparse_a, dict_sparse_b):

'''兩個字典相加'''

dict_sparse_add = dict()

dict_sparse_add2 = dict()

for i in dict_sparse_a:

if i in dict_sparse_b:

dict_sparse_add[i] = dict_sparse_a[i] + dict_sparse_b[i]

else:

dict_sparse_add[i] = dict_sparse_a[i]

for j in dict_sparse_b:

if j not in dict_sparse_add:

dict_sparse_add[j] = dict_sparse_b[j]

for i in dict_sparse_add:

if dict_sparse_add[i] != 0:

dict_sparse_add2[i] = dict_sparse_add[i] 

return dict_sparse_add2

def createarray(list_sparse, allrow = 3, allcol = 4):

'''列表模擬陣列'''

row = 0 

while row < allrow:

list_string = raw_input("enter one array items spaced by comma:/n").strip().split(',')

list_array = list()

for i in list_string:

row += 1

def createsparse(list_sparse):

'''將模擬出來的列表轉為為 字典  字典的鍵為 陣列下標'''

dict_sparse = dict()

for i in range(0, len(list_sparse)):

for j in range(0, len(list_sparse[i])):

if 0 != list_sparse[i][j]:

dict_sparse[(i, j)] = list_sparse[i][j]

return dict_sparse

def main():

print 'ok'

list_sparse_a = list()

list_sparse_b = list()

print 'array a'

createarray(list_sparse_a)

dict_sparse_a = createsparse(list_sparse_a) 

print "sparse array a"

for i in sorted(dict_sparse_a):

print i, dict_sparse_a[i]

print 'array b'

createarray(list_sparse_b)

dict_sparse_b = createsparse(list_sparse_b)

print "sparse array b"

for i in sorted(dict_sparse_b):

print i, dict_sparse_b[i]

dict_sparse_add = addsparse(dict_sparse_a, dict_sparse_b)

print "add result"

for i in sorted(dict_sparse_add):

print i, dict_sparse_add[i]

dict_sparse_sub = subsparse(dict_sparse_a, dict_sparse_b)

print "sub result"

for i in sorted(dict_sparse_sub):

print i, dict_sparse_sub[i]

if __name__ == '__main__':

main()

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